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Algebraic Expressions - Formulation

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Select the algebraic expression(s) to represent the word problem(s).


1. Robert bought t marbles. Bill bought 16 marbles less than Robert. How many marbles did Bill buy?
t + 16
t − 16
• 16
• 16 − t
Answer: t − 16
Marbles Robert bought = t
Marbles Bill bought = t − 16
'16 less than t' is equivalent to 't − 16' in symbols.

2. Pamela bought f pencils. Barbara bought 7 pencils more than Pamela. How many pencils did Barbara buy?
f  + 7
f − 7
• 7
• 7 − f
Answer: f  + 7
Pencils Pamela bought = f
Pencils Barbara bought = f  + 7
'7 more than f' is equivalent to 'f  + 7' in symbols.

3. Pamela lost 10 marbles. She had g marbles. How many marbles does Pamela have now?
g − 10
g + 10
• 10
• 10 − g
Answer: g − 10
Marbles Pamela had = g
Marbles Pamela lost = 10
Marbles Pamela has now = g − 10
'lost 10 from g' is equivalent to 'g − 10' in symbols.


4. Robert borrowed 12 golf balls from Bill. Bill had d golf balls. How many golf balls does Bill have now?
d + 12
• 12
• 12 − d
d − 12
Answer: d − 12
Golf balls Bill had = d
Golf balls Robert borrowed = 12
Golf balls Bill has now = d − 12
'borrowed 12 from d' is equivalent to 'd − 12' in symbols.

5. Pamela scored 15 extra credit points than Bill. Bill scored h credit points. How many credit points did Pamela score?
• 15 − h
h + 15
h
h − 15
Answer: h + 15
Points Barbara scored = h
Points Pamela scored = h + 15
'15 extra than h' is equivalent to 'h + 15' in symbols.

6. Robert scored 7 fewer credit points than Bill. Bill scored p credit points. How many credit points did Robert score?
p + 7
• 7
• 7 − p
p − 7
Answer: p − 7
Points Bill scored = p
Points Robert scored = p − 7
'7 fewer than p' is equivalent to 'p − 7' in symbols.

7. There were 20 dolls in a box. k dolls were taken away. How many dolls are left in the box now?
k + 20
• 20
k − 20
• 20 − k
Answer: 20 − k
Dolls in a box = 20
Dolls taken away = k
Dolls left = 20 − k
'k taken away from 20' is equivalent to '20 − k' in symbols.

8. There were 9 dolls in a box. h new dolls were added to the box. How many dolls are present in the box now?
• 9 − h
• 9 + h
• 9
h − 9
Answer: 9 + h
Dolls in a box = 9
Dolls added = h
Dolls present now = 9 + h
'added h to 9' is equivalent to '9 + h' in symbols.

9. There are 8 big boxes and x small boxes. What is the total number of boxes?
• 8 − x
• 8 + x
• 8
x − 8
Answer: 8 + x
Big boxes = 8
Small boxes = x
Total boxes = 8 + x
'total of 8 and x' is equivalent to '8 + x' in symbols.

10. Robert has y red jelly beans and 6 blue jelly beans. What is the total number of jelly beans?
y − 6
• 6
• 6 − y
y + 6
Answer: y + 6
Red jelly beans = y
Blue jelly beans = 6
Total jelly beans = y +6
'total of y and 6' is equivalent to 'y +6' in symbols.

11. Pamela ate t more cookies than Bill. Bill ate 7 cookies. How many cookies did Pamela eat?
t + 7
t − 7
t
• 7 − t
Answer: t + 7
Cookies Barbara ate = 7
Cookies Pamela ate = t + 7
't more than 7' is equivalent to 't + 7' in symbols.

12. Pamela ate 6 fewer cookies than Barbara. Barbara ate k cookies. How many cookies did Pamela eat?
• 6 − k
k
k − 6
k + 6
Answer: k − 6
Cookies Barbara ate = k
Cookies Pamela ate = k − 6
'6 fewer than k' is equivalent to 'k − 6' in symbols.

13. Pamela is 4 years younger than her sister. Pamela's sister is b years old. What is Pamela's age?
• 4 − b
4
b − 4
b + 4
Answer: b − 4
Pamela's sister's age = b
Pamela age = b − 4
'4 years younger than b' is equivalent to 'b − 4' in symbols.

14. Robert is j years younger than his sister. Robert's sister is 20 years old. What is Robert's age?
j − 20
j
j + 20
• 20 − j
Answer: 20 − j
Robert's sister's age = 20
Robert age = 20 − j
'j years younger than 20' is equivalent to '20 − j' in symbols.

15. Robert's brother is r years older than him. Robert is 29 years old. What is Robert's brother's age?
r − 29
• 29 + r
r
• 29 − r
Answer: 29 + r
Robert's age = r
Robert's brother's age = 29 + r
'r years older than 29' is equivalent to '29 + r' in symbols.

16. Robert and Barbara painted f pictures each. Michael painted 9 pictures more than Robert. How many pictures did Michael paint?
f − 9
f + 9
• 9
• 9 − f
Answer: f + 9
Pictures Robert painted = f
Pictures Michael painted = f +9
'9 more than f' is equivalent to 'f + 9' in symbols.

17. There are 38 toy cars in a store. d toy cars are sold. How many toy cars are left in the store?
d − 38
• 38 − d
d
• 38 + d
Answer: 38 − d
Toy cars in a store = 38
Toy cars sold =d
Toy cars left = 38 − d
'sold d from 38' is equivalent to '38 − d' in symbols.

18. Pamela had 9 books. Bill gave her g more books. Pamela then bought 4 new books. What is the total number of books Pamela has?
g + 13
g + 9
g + 4
g − 13
Answer: g + 13
Books Pamela had = 9
Books Barbara gave Pamela = g
Books Pamela bought = 4
Total books Pamela has = g + 9 + 4 = g + 13
'total of g and 9 and 4' is equivalent to ' g + 13' in symbols.

19. Robert had t crayons. Barbara borrowed 5 crayons from Robert. Barbara then borrowed 7 more crayons from Robert. How many crayons does Robert have now?
t − 5
t − 7
t − 12
t + 7
Answer: t − 12
Crayons Robert had = t
Crayons Bill borrowed = 5 + 7 = 12
Crayons Robert has now = t − 12
'borrowed 12 from t' is equivalent to ' t − 12' in symbols.

20. There are 32 ribbons in a box. 9 ribbons are added to the box and k ribbons are taken away. How many ribbons are left in the box now?
• 41 − k
k + 32
k + 9
k − 32
Answer: 41 − k
Ribbons in a box = 32
Ribbons added = 9
Ribbons taken away = k
Ribbons left = 32 + 9 − k =41 k
'k taken away from 41' is equivalent to '41 − k' in symbols.

21. Robert had 18 blue ribbons and y green ribbons. He lost 2 blue ribbons and 5 green ribbons. What is the total number of ribbons Robert has now?
y + 18
y − 11
• 11 − y
y + 11
Answer: y + 11
Ribbons Robert had = y +18 
Ribbons Robert lost = 2 + 5 = 11
Total ribbons  Robert now has =y + 18 − 11 = y + 11
'lost 11 from y + 18' is equivalent to 'y + 18 − 11' in symbols.

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