NY Regents Exam   Teasers   IQ Tests   Chemistry   Biology   GK   C++   Recipes   Search <  a href="/cgi/members/home.cgi" class="toplink">Members   Sign off

## Discussion topic: Contributed Answer/Explanation to Q. 49

#### Viewing messages

 Page 1 of 1 From: ushenoy Reply 1 of 9 Reply Subject: Contributed Answer/Explanation to Q. 49 ``` 1 The Earth completes one revolution (360°) around the Sun in about 365 days. So, rate of revolution = 360°/365 days = 1° per day (approx.)  ```Posted at: Fri Nov 27 15:51:37 2009 (GMT) From: ushenoy Reply 2 of 9 Reply View replies (5) Subject: Contributed Answer/Explanation to Q. 6 ``` 3 The eccentricity of an ellipse is a measure of how nearly circular the ellipse is, and is found by the following formula:
eccentricity = c/a
where
c = distance from the center C to focus F, and
a= distance from the center C to vertex V.
In the given diagram, visualize a horizontal line through F1 and F2.  Then, we have,
V     F            &nb sp;   C
<---- c ----->
<------ a -------->
Since c > 0.5a and c < a, the approximate eccentricity is c/a = 0.7
```Posted at: Fri Nov 27 16:20:01 2009 (GMT) From: ushenoy Reply 3 of 9 Reply Subject: Contributed Answer/Explanation to Q. 6 ``` 3 The eccentricity of an ellipse is a measure of how nearly circular the ellipse is, and is found by the following formula: eccentricity = c/awherec = distance from the center C to focus F, anda= distance from the center C to vertex V.In the given diagram, visualize a horizontal line through F1 and F2.  Then, we have,
V     F            &nb sp;   C
<---- c ----->
<------ a -------->
Since c > 0.5a and c < a, the approximate eccentricity is c/a = 0.7
```Posted at: Fri Nov 27 16:23:11 2009 (GMT) From: ushenoy Reply 4 of 9 Reply Subject: Contributed Answer/Explanation to Q. 6 ``` 3

The eccentricity of an ellipse is a measure of how nearly circular the ellipse is, and is found by the following formula:

eccentricity = c/a, where

c = distance from the center C to focus F, and

a= distance from the center C to vertex V.

In the given diagram, visualize a horizontal line through F1 and F2.  Then, we have,

V     F            &nb sp;   C
<---- c ----->
<------ a -------->
Since c > 0.5a and c < a, the approximate eccentricity is c/a = 0.7
```Posted at: Fri Nov 27 16:24:10 2009 (GMT) From: ushenoy Reply 5 of 9 Reply Subject: Contributed Answer/Explanation to Q. 6 ``` 3 The eccentricity of an ellipse is a measure of how nearly circular the ellipse is, and is found by the following formula: eccentricity = c/a, where c = distance from the center C to focus F, and a= distance from the center C to vertex V. In the given diagram, visualize a horizontal line through F1 and F2.  Then, we have,V     F            &nb sp;   C<---- c -----><------ a -------->Since c > 0.5a and c < a, the approximate eccentricity is c/a = 0.7  ```Posted at: Fri Nov 27 16:25:05 2009 (GMT) From: ushenoy Reply 6 of 9 Reply Subject: Contributed Answer/Explanation to Q. 6 ``` 3 The eccentricity of an ellipse is a measure of how nearly circular the ellipse is, and is found by the following formula: Eccentricity = c/a, where c = distance from the center C to focus F, and a= distance from the center C to vertex V. In the given diagram, visualize a horizontal line through F1 and F2.  Then, we have,    V     F            &nb sp;   C           <---- c ----->    <------ a --------> Since c > 0.5a and c < a, the approximate eccentricity is c/a = 0.7  ```Posted at: Fri Nov 27 16:26:03 2009 (GMT) From: ushenoy Reply 7 of 9 Reply Subject: Contributed Answer/Explanation to Q. 6 ``` 3 The eccentricity of an ellipse is a measure of how nearly circular the ellipse is, and is found by the following formula: Eccentricity = c/a, where c = distance from the center C to focus F, and a = distance from the center C to vertex V. In the given diagram, visualize a horizontal line through F1 and F2.  Then, we have,    V     F            &nb sp;   C           <---- c ----->    <------ a --------> Since c > 0.5a and c < a, the approximate eccentricity is c/a = 0.7  ```Posted at: Fri Nov 27 16:26:45 2009 (GMT) From: azmol218 Reply 8 of 9 Reply View replies (1) Subject: Contributed Answer/Explanation to Q. 9 ``` hkdjfhba iurjg:FDGDAJHERGnkj jhaHKQLTaj ```Posted at: Wed May 13 02:33:52 2015 (GMT) From: azmol218 Reply 9 of 9 Reply Subject: Contributed Answer/Explanation to Q. 9 ``` The Foucault pendulum appears to spin in its axis by rotate on the Floor. ```Posted at: Wed May 13 02:35:19 2015 (GMT) Page 1 of 1

To post to this forum, you must be signed in as a Syvum member. Please sign in / register as a member.