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| From: anandagoswami | Reply 1 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 1 |
1600
Posted at: Mon Nov 30 10:23:12 2009 (GMT)
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| From: vishwanath11 | Reply 2 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 8 |
7.14cm
area of triangleABC/area of triangle ADE=BC/DE [as the area of corresponding
sides of
similar
triangles are proportional to their areas]
25/49=BC/14
25*14/49=bc
=50/7
=7.142cm
=7.14cms
Posted at: Sun Feb 21 01:58:35 2010 (GMT)
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| From: vishwanath11 | Reply 3 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 3 |
-2
Posted at: Sun Feb 21 02:03:01 2010 (GMT)
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| From: sushmita14 | Reply 4 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 2 |
10648
p=8000, r=10%, t=3 yrs
a=p(1+r/100)n
a=8000(1+10/100)3
a=8000(11/10)(11/10)(11/10)
a= 8(11)(11)(11)
a= 10648
Posted at: Sat May 29 09:22:34 2010 (GMT)
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| From: shubhamverma | Reply 5 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 3 |
-2
Posted at: Thu Jun 10 08:04:50 2010 (GMT)
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| From: arroutray | Reply 6 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 9 |
2648
P=8000,T=3Yrs,R=10%
A=P(1+r/100)n
A=8000(1+10/100)3
A=8000*1331/1000
A=8*1331
A=10684
C.I=A-P=10684-8000=2648.
Posted at: Thu Sep 16 07:14:46 2010 (GMT)
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| From: arroutray | Reply 7 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 2 |
2648
P=8000,T=3Yrs,R=10%
A=P(1+r/100)n
A=8000(1+10/100)3
A=8000*1331/1000
A=8*1331
A=10684
C.I=A-P=10684-8000=2648.
Posted at: Thu Sep 16 07:16:21 2010 (GMT)
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| From: piyushmanicom | Reply 8 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 1 |
1600
Posted at: Thu Jan 20 08:24:56 2011 (GMT)
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| From: hasu | Reply 9 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 1 |
1760
Posted at: Fri Jan 21 06:12:31 2011 (GMT)
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| From: sharans | Reply 10 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 40 |
8
Posted at: Sun Jan 23 04:26:16 2011 (GMT)
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| From: 729116 | Reply 11 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 4 |
2(B0
let a/b=c/d=k
so,a=bk and c=dk
so,3a-5b/3a+5b=3bk-5b/3bk+5b , 3c-5d/3c+5d=3dk-5d/3dk+5d
or,b(3k-5)/b(3k+5)=(3k-5)/(3k+5) ,
d(3k-5)/d(3k+5)=(3k-5)/(3k+5).hence proved that 3a-5b/3a+5b=3c-5d/3c+5d
Posted at: Tue Feb 1 17:01:28 2011 (GMT)
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| From: suman36 | Reply 12 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 1 |
1(a)
let the selling price be x or amount of sales
tax=x.10/100=x/10
marked price=selling price+sales price=x+x/10=10x+x/10=11x/10
or,11x/10=17600
or,11x=176000
or,x=176000/11=Rs16,000
Posted at: Tue Feb 1 17:24:36 2011 (GMT)
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| From: suman36 | Reply 13 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 2 |
1(a)
I for the 1st year=PRT/100=8000.10.1/100=Rs800 , A=P+I =8000+800=Rs8800
I for the 2nd year=PRT/100=8800.10.1/100=Rs880 , A=P+I=8800+880=Rs9680
I for the 3rd year=PRT/100=9680.10.1/100=Rs968 , A=P+I=9680+968=Rs10648
Posted at: Tue Feb 1 17:31:16 2011 (GMT)
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| From: suman36 | Reply 14 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 3 |
2(a)
x-1=0 or,x=1
f(x)=2x 3-3x 2+7x-8
f(1)=2(1) 3-3(1) 2+7.1-8
=2-3+7-8
=-2 (ans)
Posted at: Tue Feb 1 17:40:43 2011 (GMT)
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| From: suman36 | Reply 15 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 6 |
3(A)
3 sin 72*/cos18*-sec 32*/cosec58*
or,3sin(90*-18*)/cos18*-sec(90*-58*)=3cos18*/cos18*-cosec58*/cosec58*
=3.1-1=2
Posted at: Wed Feb 2 17:08:23 2011 (GMT)
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| From: suman36 | Reply 16 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 8 |
10CM
since,BC//DE , SO triangle ABC ~ triangle ADE
ar of tr ABC/ar of tr ADE=BC2/DE2=25/25+24=BC 2/14 2
OR,BC2=25.14.14/49= OR,BC=√100=10CM
Posted at: Wed Feb 2 17:23:23 2011 (GMT)
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| From: suman36 | Reply 17 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 9 |
3:5
2=K×-3+1×5/K+1
OR,2K+2=-3K+5 =2K+3K=5-2 =K3/5 SO THE REQUIRED RATIO=3:5
Posted at: Wed Feb 2 17:28:07 2011 (GMT)
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| From: suman36 | Reply 18 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 10 |
3,2
RX=(X,-Y) 0R,RX(3,-2)=(3,2)
Posted at: Wed Feb 2 17:32:22 2011 (GMT)
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| From: suman36 | Reply 19 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 14 |
12CM
AX=AB+BX=4+6=10CM
XA.XB=XC.XD=10.6=XC.5 OR,XC=60/5=12CM
Posted at: Sat Feb 5 17:19:50 2011 (GMT)
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| From: suman36 | Reply 20 of 21 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 11 |
(-3,_2)
Posted at: Sat Feb 5 17:20:43 2011 (GMT)
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