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## Discussion topic: Contributed Answer/Explanation to Q. 1

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 Page 1 of 2  > From: anandagoswami Reply 1 of 21 Reply Subject: Contributed Answer/Explanation to Q. 1 1600 Posted at: Mon Nov 30 10:23:12 2009 (GMT) From: vishwanath11 Reply 2 of 21 Reply Subject: Contributed Answer/Explanation to Q. 8 7.14cm area of triangleABC/area of triangle ADE=BC/DE [as the area of corresponding sides of                                                                         similar triangles are proportional to their areas]   25/49=BC/14 25*14/49=bc =50/7 =7.142cm =7.14cms Posted at: Sun Feb 21 01:58:35 2010 (GMT) From: vishwanath11 Reply 3 of 21 Reply Subject: Contributed Answer/Explanation to Q. 3 -2 Posted at: Sun Feb 21 02:03:01 2010 (GMT) From: sushmita14 Reply 4 of 21 Reply Subject: Contributed Answer/Explanation to Q. 2 10648 p=8000, r=10%, t=3 yrs   a=p(1+r/100)n a=8000(1+10/100)3 a=8000(11/10)(11/10)(11/10) a=   8(11)(11)(11) a= 10648 Posted at: Sat May 29 09:22:34 2010 (GMT) From: shubhamverma Reply 5 of 21 Reply Subject: Contributed Answer/Explanation to Q. 3 -2 Posted at: Thu Jun 10 08:04:50 2010 (GMT) From: arroutray Reply 6 of 21 Reply Subject: Contributed Answer/Explanation to Q. 9 2648 P=8000,T=3Yrs,R=10% A=P(1+r/100)n A=8000(1+10/100)3 A=8000*1331/1000 A=8*1331 A=10684 C.I=A-P=10684-8000=2648.   Posted at: Thu Sep 16 07:14:46 2010 (GMT) From: arroutray Reply 7 of 21 Reply Subject: Contributed Answer/Explanation to Q. 2 2648 P=8000,T=3Yrs,R=10% A=P(1+r/100)n A=8000(1+10/100)3 A=8000*1331/1000 A=8*1331 A=10684 C.I=A-P=10684-8000=2648. Posted at: Thu Sep 16 07:16:21 2010 (GMT) From: piyushmanicom Reply 8 of 21 Reply Subject: Contributed Answer/Explanation to Q. 1 1600 Posted at: Thu Jan 20 08:24:56 2011 (GMT) From: hasu Reply 9 of 21 Reply Subject: Contributed Answer/Explanation to Q. 1 1760 Posted at: Fri Jan 21 06:12:31 2011 (GMT) From: sharans Reply 10 of 21 Reply Subject: Contributed Answer/Explanation to Q. 40 8 Posted at: Sun Jan 23 04:26:16 2011 (GMT) From: 729116 Reply 11 of 21 Reply Subject: Contributed Answer/Explanation to Q. 4 2(B0   let a/b=c/d=k   so,a=bk and c=dk so,3a-5b/3a+5b=3bk-5b/3bk+5b  , 3c-5d/3c+5d=3dk-5d/3dk+5d          or,b(3k-5)/b(3k+5)=(3k-5)/(3k+5)     , d(3k-5)/d(3k+5)=(3k-5)/(3k+5).hence proved that 3a-5b/3a+5b=3c-5d/3c+5d      Posted at: Tue Feb 1 17:01:28 2011 (GMT) From: suman36 Reply 12 of 21 Reply Subject: Contributed Answer/Explanation to Q. 1 1(a) let the selling price be x        or amount of sales tax=x.10/100=x/10 marked price=selling price+sales price=x+x/10=10x+x/10=11x/10 or,11x/10=17600 or,11x=176000 or,x=176000/11=Rs16,000 Posted at: Tue Feb 1 17:24:36 2011 (GMT) From: suman36 Reply 13 of 21 Reply Subject: Contributed Answer/Explanation to Q. 2 1(a) I  for the 1st year=PRT/100=8000.10.1/100=Rs800 , A=P+I =8000+800=Rs8800 I for the 2nd year=PRT/100=8800.10.1/100=Rs880 , A=P+I=8800+880=Rs9680 I for the 3rd year=PRT/100=9680.10.1/100=Rs968 , A=P+I=9680+968=Rs10648 Posted at: Tue Feb 1 17:31:16 2011 (GMT) From: suman36 Reply 14 of 21 Reply Subject: Contributed Answer/Explanation to Q. 3 2(a) x-1=0 or,x=1 f(x)=2x 3-3x 2+7x-8 f(1)=2(1) 3-3(1) 2+7.1-8      =2-3+7-8      =-2 (ans) Posted at: Tue Feb 1 17:40:43 2011 (GMT) From: suman36 Reply 15 of 21 Reply Subject: Contributed Answer/Explanation to Q. 6 3(A)     3 sin 72*/cos18*-sec 32*/cosec58*               or,3sin(90*-18*)/cos18*-sec(90*-58*)=3cos18*/cos18*-cosec58*/cosec58*   =3.1-1=2 Posted at: Wed Feb 2 17:08:23 2011 (GMT) From: suman36 Reply 16 of 21 Reply Subject: Contributed Answer/Explanation to Q. 8 10CM   since,BC//DE  ,  SO triangle ABC ~ triangle ADE         ar   of tr ABC/ar of tr ADE=BC2/DE2=25/25+24=BC 2/14 2  OR,BC2=25.14.14/49= OR,BC=√100=10CM  Posted at: Wed Feb 2 17:23:23 2011 (GMT) From: suman36 Reply 17 of 21 Reply Subject: Contributed Answer/Explanation to Q. 9 3:5   2=K×-3+1×5/K+1      OR,2K+2=-3K+5 =2K+3K=5-2 =K3/5    SO THE REQUIRED RATIO=3:5 Posted at: Wed Feb 2 17:28:07 2011 (GMT) From: suman36 Reply 18 of 21 Reply Subject: Contributed Answer/Explanation to Q. 10 3,2 RX=(X,-Y) 0R,RX(3,-2)=(3,2) Posted at: Wed Feb 2 17:32:22 2011 (GMT) From: suman36 Reply 19 of 21 Reply Subject: Contributed Answer/Explanation to Q. 14 12CM   AX=AB+BX=4+6=10CM        XA.XB=XC.XD=10.6=XC.5                 OR,XC=60/5=12CM Posted at: Sat Feb 5 17:19:50 2011 (GMT) From: suman36 Reply 20 of 21 Reply Subject: Contributed Answer/Explanation to Q. 11 (-3,_2) Posted at: Sat Feb 5 17:20:43 2011 (GMT) Page 1 of 2  >

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