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From: anandagoswamiReply 1 of 21Reply
Subject: Contributed Answer/Explanation to Q. 1
   1600

Posted at: Mon Nov 30 10:23:12 2009 (GMT)

From: vishwanath11Reply 2 of 21Reply
Subject: Contributed Answer/Explanation to Q. 8
   7.14cm
   
   area of triangleABC/area of triangle ADE=BC/DE [as the area of corresponding
   sides of
                                         
                                    similar
   triangles are proportional to their areas]
   
   
    
   
   
   25/49=BC/14
   
   
   25*14/49=bc 
   
   
   =50/7
   
   
   =7.142cm
   
   
   =7.14cms 

Posted at: Sun Feb 21 01:58:35 2010 (GMT)

From: vishwanath11Reply 3 of 21Reply
Subject: Contributed Answer/Explanation to Q. 3
   -2

Posted at: Sun Feb 21 02:03:01 2010 (GMT)

From: sushmita14Reply 4 of 21Reply
Subject: Contributed Answer/Explanation to Q. 2
   10648
   
   p=8000, r=10%, t=3 yrs
   
   
    
   
   
   a=p(1+r/100)n
   
   
   a=8000(1+10/100)3
   
   
   a=8000(11/10)(11/10)(11/10) 
   
   
   a=   8(11)(11)(11)
   
   
   a= 10648

Posted at: Sat May 29 09:22:34 2010 (GMT)

From: shubhamvermaReply 5 of 21Reply
Subject: Contributed Answer/Explanation to Q. 3
   -2

Posted at: Thu Jun 10 08:04:50 2010 (GMT)

From: arroutrayReply 6 of 21Reply
Subject: Contributed Answer/Explanation to Q. 9
   2648
   
   P=8000,T=3Yrs,R=10%
   
   
   A=P(1+r/100)n
   
   
   A=8000(1+10/100)3
   
   
   A=8000*1331/1000
   
   
   A=8*1331
   
   
   A=10684
   
   
   C.I=A-P=10684-8000=2648.
   
   
    

Posted at: Thu Sep 16 07:14:46 2010 (GMT)

From: arroutrayReply 7 of 21Reply
Subject: Contributed Answer/Explanation to Q. 2
   2648
   
   P=8000,T=3Yrs,R=10% 
   
   
   A=P(1+r/100)n 
   
   
   A=8000(1+10/100)3 
   
   
   A=8000*1331/1000 
   
   
   A=8*1331 
   
   
   A=10684 
   
   
   C.I=A-P=10684-8000=2648. 

Posted at: Thu Sep 16 07:16:21 2010 (GMT)

From: piyushmanicomReply 8 of 21Reply
Subject: Contributed Answer/Explanation to Q. 1
   1600

Posted at: Thu Jan 20 08:24:56 2011 (GMT)

From: hasuReply 9 of 21Reply
Subject: Contributed Answer/Explanation to Q. 1
   1760

Posted at: Fri Jan 21 06:12:31 2011 (GMT)

From: sharansReply 10 of 21Reply
Subject: Contributed Answer/Explanation to Q. 40
   8

Posted at: Sun Jan 23 04:26:16 2011 (GMT)

From: 729116Reply 11 of 21Reply
Subject: Contributed Answer/Explanation to Q. 4
   2(B0
   
    
   
   
   let a/b=c/d=k
   
   
    
   
   
   so,a=bk and c=dk
   
   
   so,3a-5b/3a+5b=3bk-5b/3bk+5b  , 3c-5d/3c+5d=3dk-5d/3dk+5d      
   
   
    
   
   
    or,b(3k-5)/b(3k+5)=(3k-5)/(3k+5)     ,
   d(3k-5)/d(3k+5)=(3k-5)/(3k+5).hence proved that 3a-5b/3a+5b=3c-5d/3c+5d  
     

Posted at: Tue Feb 1 17:01:28 2011 (GMT)

From: suman36Reply 12 of 21Reply
Subject: Contributed Answer/Explanation to Q. 1
   1(a)
   
   let the selling price be x        or amount of sales
   tax=x.10/100=x/10 
   
   
   marked price=selling price+sales price=x+x/10=10x+x/10=11x/10 
   
   
   or,11x/10=17600 
   
   
   or,11x=176000 
   
   
   or,x=176000/11=Rs16,000 

Posted at: Tue Feb 1 17:24:36 2011 (GMT)

From: suman36Reply 13 of 21Reply
Subject: Contributed Answer/Explanation to Q. 2
   1(a)
   
   I  for the 1st year=PRT/100=8000.10.1/100=Rs800 , A=P+I =8000+800=Rs8800 
   
   
   I for the 2nd year=PRT/100=8800.10.1/100=Rs880 , A=P+I=8800+880=Rs9680 
   
   
   I for the 3rd year=PRT/100=9680.10.1/100=Rs968 , A=P+I=9680+968=Rs10648

Posted at: Tue Feb 1 17:31:16 2011 (GMT)

From: suman36Reply 14 of 21Reply
Subject: Contributed Answer/Explanation to Q. 3
   2(a)
   
   x-1=0 or,x=1 
   
   
   f(x)=2x 3-3x 2+7x-8 
   
   
   f(1)=2(1) 3-3(1) 2+7.1-8 
   
   
        =2-3+7-8 
   
   
        =-2 (ans)

Posted at: Tue Feb 1 17:40:43 2011 (GMT)

From: suman36Reply 15 of 21Reply
Subject: Contributed Answer/Explanation to Q. 6
   3(A)
   
    
   
   
    
   
   
   3 sin 72*/cos18*-sec 32*/cosec58*    
   
   
    
   
   
    
   
   
    
   
   
    
   
   
    
   
   
   or,3sin(90*-18*)/cos18*-sec(90*-58*)=3cos18*/cos18*-cosec58*/cosec58*  
   =3.1-1=2

Posted at: Wed Feb 2 17:08:23 2011 (GMT)

From: suman36Reply 16 of 21Reply
Subject: Contributed Answer/Explanation to Q. 8
   10CM
   
    
   
   
   since,BC//DE  ,  SO triangle ABC ~ triangle ADE    
   
   
    
   
   
    
   
   
   ar   of tr ABC/ar of tr ADE=BC2/DE2=25/25+24=BC 2/14 2 
   OR,BC2=25.14.14/49= OR,BC=√100=10CM 

Posted at: Wed Feb 2 17:23:23 2011 (GMT)

From: suman36Reply 17 of 21Reply
Subject: Contributed Answer/Explanation to Q. 9
   3:5
   
    
   
   
   2=K×-3+1×5/K+1 
   
   
    
   
   
    
   
   
   OR,2K+2=-3K+5 =2K+3K=5-2 =K3/5    SO THE REQUIRED RATIO=3:5

Posted at: Wed Feb 2 17:28:07 2011 (GMT)

From: suman36Reply 18 of 21Reply
Subject: Contributed Answer/Explanation to Q. 10
   3,2
   RX=(X,-Y) 0R,RX(3,-2)=(3,2)

Posted at: Wed Feb 2 17:32:22 2011 (GMT)

From: suman36Reply 19 of 21Reply
Subject: Contributed Answer/Explanation to Q. 14
   12CM
   
    
   
   
   AX=AB+BX=4+6=10CM   
   
   
    
   
   
    
   
   
   XA.XB=XC.XD=10.6=XC.5                 OR,XC=60/5=12CM

Posted at: Sat Feb 5 17:19:50 2011 (GMT)

From: suman36Reply 20 of 21Reply
Subject: Contributed Answer/Explanation to Q. 11
   (-3,_2)

Posted at: Sat Feb 5 17:20:43 2011 (GMT)

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