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| From: poojan | Reply 101 of 141 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 4 |
Answer :-
Infra-red radiations are preferred over ordinary
radiations as they do not get scatter much
while travelling in the air.
Posted at: Fri Mar 5 16:38:37 2010 (GMT)
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| From: sonali16 | Reply 102 of 141 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 25 |
One kilowatt hour is the electric energy consumed bu an electrical appliance
of power 1kW when it is used for 1 hour. 1kWh= 10 to the power of 6 joule
Posted at: Sat Mar 6 05:41:22 2010 (GMT)
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| From: sonali16 | Reply 103 of 141 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 27 |
Solar energy to chemical energy.
Posted at: Sat Mar 6 05:42:18 2010 (GMT)
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| From: sonali16 | Reply 104 of 141 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 28 |
Electrical to chemical energy.
Posted at: Sat Mar 6 05:48:33 2010 (GMT)
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| From: sonali16 | Reply 105 of 141 | Reply | View replies (1)
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| Subject: Contributed Answer/Explanation to Q. 29 |
Efficiency = MA/Vr *100%
Posted at: Sat Mar 6 05:49:35 2010 (GMT)
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| From: sonali16 | Reply 106 of 141 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 29 |
Efficiency = MA/VR *100%
Posted at: Sat Mar 6 05:49:46 2010 (GMT)
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| From: sonali16 | Reply 107 of 141 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 31 |
To increase the efficiency of the pulley system, the lower block of this
pulley should be of negligible weight.
Posted at: Sat Mar 6 05:51:13 2010 (GMT)
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| From: ratchet | Reply 108 of 141 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 6 |
Water is not suitable as a barometric liquid because:-
*The rise in the level of water is more.
*Water evaporates easily.
Posted at: Sat Mar 6 12:31:43 2010 (GMT)
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| From: sori4 | Reply 109 of 141 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 5 |
ans
relativ dencity is the real depth of the substance under water or any other
liquid...
Posted at: Sat Mar 6 16:57:08 2010 (GMT)
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| From: sori4 | Reply 110 of 141 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 7 |
ans
according to snells's lw angle of reflction is normal to angle of
incidence...
Posted at: Sat Mar 6 16:58:58 2010 (GMT)
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| From: sori4 | Reply 111 of 141 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 8 |
black
Posted at: Sat Mar 6 16:59:24 2010 (GMT)
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| From: sori4 | Reply 112 of 141 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 9 |
blue
Posted at: Sat Mar 6 16:59:46 2010 (GMT)
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| From: sori4 | Reply 113 of 141 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 12 |
displacemnt of a substance from its mean position to its extreme position..
Posted at: Sat Mar 6 17:01:12 2010 (GMT)
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| From: sori4 | Reply 114 of 141 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 21 |
10*20=200
Posted at: Sat Mar 6 17:04:05 2010 (GMT)
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| From: sori4 | Reply 115 of 141 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 22 |
15-6=9
Posted at: Sat Mar 6 17:04:51 2010 (GMT)
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| From: sori4 | Reply 116 of 141 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 26 |
w=f*s
Posted at: Sat Mar 6 17:07:17 2010 (GMT)
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| From: kaustubh_mokashi | Reply 117 of 141 | Reply | View replies (2)
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| Subject: Contributed Answer/Explanation to Q. 1 |
ans
II class lever has the mechanical advantage more than 1. Its MA can be
increased by making the effort arm longer or by slightly shifting the load
townards the fulcrum
Posted at: Sun Mar 7 10:51:33 2010 (GMT)
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| From: kaustubh_mokashi | Reply 118 of 141 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 1 |
ans
II class lever has the mechanical advantage more than 1. Its MA can be
increased by making the effort arm longer or by slightly shifting the load
townards the fulcrum
Posted at: Sun Mar 7 10:51:55 2010 (GMT)
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| From: kaustubh_mokashi | Reply 119 of 141 | Reply | View replies (1)
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| Subject: Contributed Answer/Explanation to Q. 2 |
ans
m= m m=m
S1=20
S2=30
potential energy = m*g*h1 potential
energy= m*g*h1
=20mg
= 30mg
therefore , ratio = 20mg/30mg
Posted at: Sun Mar 7 10:56:53 2010 (GMT)
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| From: kaustubh_mokashi | Reply 120 of 141 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 2 |
ans
m= m m=m
S1=20
S2=30
potential energy = m*g*h1 potential
energy= m*g*h1
=20mg
= 30mg
therefore , ratio = 20mg/30mg
= 2:3
Posted at: Sun Mar 7 10:57:20 2010 (GMT)
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