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From: haroonamanReply 61 of 141Reply
Subject: Contributed Answer/Explanation to Q. 41
   The speed of light in glass increases with the increase in the wavelength of
   light.

Posted at: Fri Feb 12 04:53:50 2010 (GMT)

From: haroonamanReply 62 of 141Reply
Subject: Contributed Answer/Explanation to Q. 43
   Refractive index of water = Real Depth /  Apparent Depth . 

Posted at: Fri Feb 12 05:28:31 2010 (GMT)

From: haroonamanReply 63 of 141Reply         View replies (3)
Subject: Contributed Answer/Explanation to Q. 44
   The distance is : 
   
   Given , 
   
   
                                         
       t = 3 sec
   
   
                                         
       Let d m be the distance. 
   
   
   For 1st Echo,
   
   
                             2d / V = 3
   
   
   After moving 82.5m closer to the cliff, for second echo , 2(d - 82.5) / V
   
   
                                         
                                         
           = 2.5
   
   
              d  / d- 82.5 = 3 / 2.5d = 3d - 247.5 or 0.5 d = 247.5
   .
   
   
                                        ...
   d = 495 m
   
   
    
   
   
   Velocity of light = 2d / 3 = 2 x 495  = 330 ms-1
   
   
                                         
          3

Posted at: Fri Feb 12 05:41:24 2010 (GMT)

From: haroonamanReply 64 of 141Reply
Subject: Contributed Answer/Explanation to Q. 44
   The distance is : 
   
   Given , 
   
   
                                         
       t = 3 sec 
   
   
                                         
       Let d m be the distance. 
   
   
   For 1st Echo, 
   
   
                             2d / V = 3 
   
   
   After moving 82.5m closer to the cliff, for second echo , 2(d - 82.5) / V 
   
   
                                         
                                         
           = 2.5 
   
   
              d  / d- 82.5 = 3 / 2.5d = 3d - 247.5 or 0.5 d = 247.5
   . 
   
   
                                        ...
   d = 495 m 
   
   
    
   
   
   Velocity of Sound = 2d / 3 = 2 x 495  = 330 ms-1 
   
   
                                         
          3 

Posted at: Fri Feb 12 05:41:48 2010 (GMT)

From: haroonamanReply 65 of 141Reply
Subject: Contributed Answer/Explanation to Q. 44
   The distance is : 
   
   Given , 
   
   
                                         
       t = 3 sec 
   
   
                                         
       Let d m be the distance. 
   
   
   For 1st Echo, 
   
   
                             2d / V = 3 
   
   
   After moving 82.5m closer to the cliff, for second echo , 2(d - 82.5) / V 
   
   
                                         
                                         
           = 2.5 
   
   
              d  / d- 82.5 = 3 / 2.5d = 3d - 247.5 or 0.5 d = 247.5
   . 
   
   
                                        ...
   d = 495 m 
   
   
    
   
   
   Velocity of Sound = 2d / 3 = 2 x 495  = 330 ms-1 
   
   
                                         
          3 

Posted at: Fri Feb 12 05:43:55 2010 (GMT)

From: haroonamanReply 66 of 141Reply
Subject: Contributed Answer/Explanation to Q. 44
   The distance is : 
   
   Given , 
   
   
                                         
       t = 3 sec 
   
   
                                         
       Let d m be the distance. 
   
   
   For 1st Echo, 
   
   
                             2d / V = 3 
   
   
   After moving 82.5m closer to the cliff, for second echo , 2(d - 82.5) / V 
   
   
                                         
                                         
           = 2.5 
   
   
              d  / d- 82.5 = 3 / 2.5d = 3d - 247.5 or 0.5 d = 247.5
   . 
   
   
                                        ...
   d = 495 m 
   
   
    
   
   
   Velocity of Sound = 2d / 3 = 2 x 495  = 330 ms-1 
   
   
                                         
             3 

Posted at: Fri Feb 12 05:44:14 2010 (GMT)

From: haroonamanReply 67 of 141Reply
Subject: Contributed Answer/Explanation to Q. 45
   velocity is = 
   
   Velocity of Sound =  2d   = 2 x 495  = 330 ms-1 
   
   
                                     3   
          3 

Posted at: Fri Feb 12 05:46:14 2010 (GMT)

From: haroonamanReply 68 of 141Reply
Subject: Contributed Answer/Explanation to Q. 46
   Specific heat capacity of a substance  is the quantity of heat required to
   raise temperature of 1kg of that substance by 1 degree C.

Posted at: Fri Feb 12 05:50:41 2010 (GMT)

From: haroonamanReply 69 of 141Reply
Subject: Contributed Answer/Explanation to Q. 47
   The heat supplied to a substance during its change of state dous not cause
   any rise in temperature as this heat is used up in increasing the internal
   potential energy .

Posted at: Fri Feb 12 06:01:42 2010 (GMT)

From: haroonamanReply 70 of 141Reply
Subject: Contributed Answer/Explanation to Q. 48
   Mass of the substance
   
    
   
   
   Q = m x c x t 
   
   
   800 = m x 500 x 80
   
   
      m =       800
   
   
               500 x 80
   
   
          =  0.02 kg. 

Posted at: Fri Feb 12 07:22:53 2010 (GMT)

From: haroonamanReply 71 of 141Reply
Subject: Contributed Answer/Explanation to Q. 49
   the specific latent heat of fusion 
   
    
   
   
   Q = m x L
   
   
   800 = 0.02 x L
   
   
   L =    800
   
   
            0.02
   
   
   L =   40000 J kg-1 

Posted at: Fri Feb 12 07:28:21 2010 (GMT)

From: haroonamanReply 72 of 141Reply         View replies (2)
Subject: Contributed Answer/Explanation to Q. 50
   Earthing of an electrical appliance means connecting the earth wire of cable
   to the outer metal case of an appliance.

Posted at: Fri Feb 12 07:30:24 2010 (GMT)

From: haroonamanReply 73 of 141Reply
Subject: Contributed Answer/Explanation to Q. 50
   Earthing of an electrical appliance means connecting the earth wire of cable
   to the outer metal case of an appliance. In case the live wire comes in
   contact with the metal case then the heavy current is transmitted to the
   earth and prevents shocks./ 

Posted at: Fri Feb 12 07:32:28 2010 (GMT)

From: haroonamanReply 74 of 141Reply
Subject: Contributed Answer/Explanation to Q. 50
   Earthing of an electrical appliance means connecting the earth wire of cable
   to the outer metal case of an appliance. In case the live wire comes in
   contact with the metal case then the heavy current is transmitted to the
   earth and prevents shocks.

Posted at: Fri Feb 12 07:32:53 2010 (GMT)

From: haroonamanReply 75 of 141Reply
Subject: Contributed Answer/Explanation to Q. 51
   If instead of a direct current an alternating current is used, the soft iron
   core does not get magnetised and hence the bell does not ring.

Posted at: Fri Feb 12 07:36:04 2010 (GMT)

From: haroonamanReply 76 of 141Reply
Subject: Contributed Answer/Explanation to Q. 52
   Two factors on which the strength of an induced current depends on are :
   
   (i) Change in amount of magnetic flux.
   
   
   (ii) Time in which the magnetic flux changes.

Posted at: Fri Feb 12 07:39:57 2010 (GMT)

From: haroonamanReply 77 of 141Reply
Subject: Contributed Answer/Explanation to Q. 53
    When a solenoid that is carrying current is freely suspended it behaves
   like a bar magnet and hence rests in the north - south direction.

Posted at: Fri Feb 12 07:43:27 2010 (GMT)

From: haroonamanReply 78 of 141Reply
Subject: Contributed Answer/Explanation to Q. 54
   Current is =
   
                                     Given,
                           
   
   
                                         
          v =  1.5 V
   
   
                                         
          r =  1 ohm
   
   
                                         
         R = 4 ohm, 20 ohm
   
   
                         
   
   
                                         
   Total resistence = 4 + 20 + 1
   
   
                                         
                             = 25 ohm
   
   
                                         
       V =  RI
   
   
                                         
     1.5 = 25 x I
   
   
                                         
       I   =  1.5
   
   
                                         
                25 
   
   
                                         
       I   = 0.6 A

Posted at: Fri Feb 12 09:52:47 2010 (GMT)

From: haroonamanReply 79 of 141Reply
Subject: Contributed Answer/Explanation to Q. 55
   Potential difference is =
   
                                      
   Given, 
   
   
                                         
           R  =  4.0 ohm  
   
   
                                         
           I   = 0.6 A
   
   
                                         
            V = RI
   
   
                                         
       ...  V =  4.0 x 0.6
   
   
                                        
   Potential Difference =  2.4 V

Posted at: Fri Feb 12 09:58:21 2010 (GMT)

From: haroonamanReply 80 of 141Reply
Subject: Contributed Answer/Explanation to Q. 56
   Voltage drop :
   
                                        Gi
   ven,                 
   
   
                                         
             I = 0.6 A
   
   
                                         
             r = 1 ohm
   
   
                                         
            V = I x r
   
   
                                         
   ... Voltage drop = 0.6 V

Posted at: Fri Feb 12 10:02:02 2010 (GMT)

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