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## Discussion topic: Contributed Answer/Explanation to Q. 26

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 Page 1 of 1 From: sabarish Reply 1 of 11 Reply Subject: Contributed Answer/Explanation to Q. 26 ``` 1.6cm 1)Draw base BC of 6.4 cm 2)construct ∠60. at B 3)Measure CA 5.8cm and cut the 60. arc 4)Hence,Δle ABC is constucted 5)Construct the angular bisectors of any two angles. 6)The point of intersection is the incentre. 7)construct a prpendicular bisector from the incentre to any 1 side 8)From where the bisector meets the side to the incentre is the radius of the circle 9)Hence construct the incircle 10)The radius measured=1.6cm ```Posted at: Wed Dec 23 17:17:19 2009 (GMT) From: mintu Reply 2 of 11 Reply Subject: Contributed Answer/Explanation to Q. 15 ``` answer=2. ```Posted at: Mon Dec 28 08:51:49 2009 (GMT) From: kaustubh_mokashi Reply 3 of 11 Reply View replies (3) Subject: Contributed Answer/Explanation to Q. 3 ``` P =12800 Rs R =10 % T = 3 years   A= P (1 + R/100)n A= 12800 (1 + 1/10) 1   A= 12800 ( 11/10 )1   A = 1280 * 11   A= 14080 ```Posted at: Mon Mar 29 03:05:10 2010 (GMT) From: kaustubh_mokashi Reply 4 of 11 Reply Subject: Contributed Answer/Explanation to Q. 3 ``` P =12800 Rs R =10 % T = 3 years   A= P (1 + R/100)n A= 12800 (1 + 1/10) 1   A= 12800 ( 11/10 )1   A = 1280 * 11   A= 14080 ```Posted at: Mon Mar 29 03:05:17 2010 (GMT) From: kaustubh_mokashi Reply 5 of 11 Reply Subject: Contributed Answer/Explanation to Q. 3 ``` P =12800 Rs R =10 % T = 3 years   A= P (1 + R/100)n A= 12800 (1 + 1/10) 1   A= 12800 ( 11/10 )1   A = 1280 * 11   A= 14080Rs ```Posted at: Mon Mar 29 03:05:36 2010 (GMT) From: kaustubh_mokashi Reply 6 of 11 Reply Subject: Contributed Answer/Explanation to Q. 3 ``` P =12800 Rs R =10 % T = 3 years   A= P (1 + R/100)n A= 12800 (1 + 1/10) 1   A= 12800 ( 11/10 )1   A = 1280 * 11   A= 14080 Rs ```Posted at: Mon Mar 29 03:05:42 2010 (GMT) From: yashm Reply 7 of 11 Reply Subject: Contributed Answer/Explanation to Q. 13 ``` P,Q,R when joined...produces a Right Angled Triangle ```Posted at: Wed Dec 15 17:57:51 2010 (GMT) From: hasanpreet Reply 8 of 11 Reply Subject: Contributed Answer/Explanation to Q. 1 ```   thanks   ```Posted at: Sun Jan 23 14:18:21 2011 (GMT) From: shantiananthus Reply 9 of 11 Reply Subject: Contributed Answer/Explanation to Q. 7 ```  1.732/4*196=0.433*196=84.8681/2*22/7*49=11/7*49=77 AREA OF THE SHADED PORTION= 84.868+77=161.868```Posted at: Tue Jan 25 15:34:41 2011 (GMT) From: vijayashree Reply 10 of 11 Reply Subject: Contributed Answer/Explanation to Q. 36 ``` 120-110=10```Posted at: Sat Feb 12 07:12:51 2011 (GMT) From: vijayashree Reply 11 of 11 Reply Subject: Contributed Answer/Explanation to Q. 36 ``` 120-110=10```Posted at: Sat Feb 12 07:14:45 2011 (GMT) Page 1 of 1

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