Discussion topic: Contributed Answer/Explanation to Q. 26
Viewing messages
To go to the homepage of this topic, click here.
| Page 1 of 1 | | From: sabarish | Reply 1 of 11 | Reply | | | Subject: Contributed Answer/Explanation to Q. 26 | 1.6cm
1)Draw base BC of 6.4 cm
2)construct ∠60. at B
3)Measure CA 5.8cm and cut the 60. arc
4)Hence,Δle ABC is constucted
5)Construct the angular bisectors of any two angles.
6)The point of intersection is the incentre.
7)construct a prpendicular bisector from the incentre to any 1 side
8)From where the bisector meets the side to the incentre is the radius of
the circle
9)Hence construct the incircle
10)The radius measured=1.6cm
Posted at: Wed Dec 23 17:17:19 2009 (GMT)
|
| From: mintu | Reply 2 of 11 | Reply | | | Subject: Contributed Answer/Explanation to Q. 15 |
answer=2.
Posted at: Mon Dec 28 08:51:49 2009 (GMT)
|
| From: kaustubh_mokashi | Reply 3 of 11 | Reply | View replies (3)
| | Subject: Contributed Answer/Explanation to Q. 3 |
P =12800 Rs
R =10 %
T = 3 years
A= P (1 + R/100)n
A= 12800 (1 + 1/10) 1
A= 12800 ( 11/10 )1
A = 1280 * 11
A= 14080
Posted at: Mon Mar 29 03:05:10 2010 (GMT)
|
| From: kaustubh_mokashi | Reply 4 of 11 | Reply | | | Subject: Contributed Answer/Explanation to Q. 3 |
P =12800 Rs
R =10 %
T = 3 years
A= P (1 + R/100)n
A= 12800 (1 + 1/10) 1
A= 12800 ( 11/10 )1
A = 1280 * 11
A= 14080
Posted at: Mon Mar 29 03:05:17 2010 (GMT)
|
| From: kaustubh_mokashi | Reply 5 of 11 | Reply | | | Subject: Contributed Answer/Explanation to Q. 3 |
P =12800 Rs
R =10 %
T = 3 years
A= P (1 + R/100)n
A= 12800 (1 + 1/10) 1
A= 12800 ( 11/10 )1
A = 1280 * 11
A= 14080Rs
Posted at: Mon Mar 29 03:05:36 2010 (GMT)
|
| From: kaustubh_mokashi | Reply 6 of 11 | Reply | | | Subject: Contributed Answer/Explanation to Q. 3 |
P =12800 Rs
R =10 %
T = 3 years
A= P (1 + R/100)n
A= 12800 (1 + 1/10) 1
A= 12800 ( 11/10 )1
A = 1280 * 11
A= 14080 Rs
Posted at: Mon Mar 29 03:05:42 2010 (GMT)
|
| From: yashm | Reply 7 of 11 | Reply | | | Subject: Contributed Answer/Explanation to Q. 13 |
P,Q,R when joined...produces a Right Angled Triangle
Posted at: Wed Dec 15 17:57:51 2010 (GMT)
|
| From: hasanpreet | Reply 8 of 11 | Reply | | | Subject: Contributed Answer/Explanation to Q. 1 |
thanks
Posted at: Sun Jan 23 14:18:21 2011 (GMT)
|
| From: shantiananthus | Reply 9 of 11 | Reply | | | Subject: Contributed Answer/Explanation to Q. 7 |
1.732/4*196=0.433*196=84.8681/2*22/7*49=11/7*49=77 AREA OF THE SHADED
PORTION= 84.868+77=161.868 Posted at: Tue Jan 25 15:34:41 2011 (GMT)
|
| From: vijayashree | Reply 10 of 11 | Reply | | | Subject: Contributed Answer/Explanation to Q. 36 |
120-110=10 Posted at: Sat Feb 12 07:12:51 2011 (GMT)
|
| From: vijayashree | Reply 11 of 11 | Reply | | | Subject: Contributed Answer/Explanation to Q. 36 |
120-110=10 Posted at: Sat Feb 12 07:14:45 2011 (GMT)
|
| Page 1 of 1
|
|
To post to this forum, you must be signed in as a Syvum member.
Please sign in / register as a member.
