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Discussion topic: Contributed Answer/Explanation to Q. 1

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 Page 1 of 1 From: sam22 Reply 1 of 14 Reply View replies (1) Subject: Contributed Answer/Explanation to Q. 1 ``` Rs. 784 Interest For 1st Year = Principal * Rate/100 * Time                                  = 5600 * 14/100 * 1 ```Posted at: Sun Feb 14 08:46:30 2010 (GMT) From: sam22 Reply 2 of 14 Reply Subject: Contributed Answer/Explanation to Q. 2 ``` Rs. 6384 Amount = Principal + Interest              = 5600 + 784              = 6384 ```Posted at: Sun Feb 14 08:48:38 2010 (GMT) From: sam22 Reply 3 of 14 Reply Subject: Contributed Answer/Explanation to Q. 1 ``` Rs. 784 Interest For 1st Year = Principal * Rate/100 * Time                                  = 5600 * 14/100 * 1                                  = 784 ```Posted at: Sun Feb 14 08:48:54 2010 (GMT) From: sam22 Reply 4 of 14 Reply Subject: Contributed Answer/Explanation to Q. 3 ``` Rs. 894 Interest For 2nd Year = Principal * Rate/100 * Time                                   = 6384 * 14/100 * 1                                   = 893.76                                   = 894 (Correct to the nearest Rs.) ```Posted at: Sun Feb 14 08:51:20 2010 (GMT) From: sam22 Reply 5 of 14 Reply Subject: Contributed Answer/Explanation to Q. 4 ``` Rs. 3500 Selling Price = Marked Price * (1- Discount/100) 2975 = M.P. * (1 - 15/100) 2975 = M.P. * (85/100) 2975 * 100/85 = M.P. Thus, M.P. = 3500 ```Posted at: Sun Feb 14 08:55:39 2010 (GMT) From: sam22 Reply 6 of 14 Reply Subject: Contributed Answer/Explanation to Q. 5 ``` Rs. 2500 ```Posted at: Sun Feb 14 08:57:41 2010 (GMT) From: sam22 Reply 7 of 14 Reply Subject: Contributed Answer/Explanation to Q. 6 ``` Rs. 475 Profit = Selling Price - Cost Price           = 2975 - 2500           = 475 ```Posted at: Sun Feb 14 08:59:41 2010 (GMT) From: sam22 Reply 8 of 14 Reply Subject: Contributed Answer/Explanation to Q. 7 ``` 7.5 km ```Posted at: Sun Feb 14 09:03:15 2010 (GMT) From: sam22 Reply 9 of 14 Reply Subject: Contributed Answer/Explanation to Q. 8 ``` 0.0000000006 sq. km. ```Posted at: Sun Feb 14 09:45:16 2010 (GMT) From: sam22 Reply 10 of 14 Reply Subject: Contributed Answer/Explanation to Q. 16 ``` a = 5 & b = 2 ```Posted at: Sun Feb 14 09:49:56 2010 (GMT) From: sam22 Reply 11 of 14 Reply Subject: Contributed Answer/Explanation to Q. 17 ``` P(-5,2) ```Posted at: Sun Feb 14 09:50:26 2010 (GMT) From: sam22 Reply 12 of 14 Reply Subject: Contributed Answer/Explanation to Q. 19 ``` PN = 15 cm

In triangle RLQ & triangle PLN,

1). Angle RLQ = Angle PLN (Vertically Opp. Angles)

2). Angle QRL = Angle NPL (Alternate Angles)

Thus, the two triangles are similar. (By A.A. Similarity)

Therefore,

RL/LP = RQ/PN = QL/LN

2/3 = 10/PN

PN = (10*3)/2

PN= 15 cm

```Posted at: Sun Feb 14 09:58:55 2010 (GMT) From: sam22 Reply 13 of 14 Reply Subject: Contributed Answer/Explanation to Q. 20 ``` Triangle QLP is similar to triangle RLM. (RM = 32/3) RL/LP = RM/PQ = LM/LQ 2/3 = RM/16 Thus, RM=32/3 ```Posted at: Sun Feb 14 10:01:56 2010 (GMT) From: kp24 Reply 14 of 14 Reply Subject: Contributed Answer/Explanation to Q. 1 ``` 784 Interest for first year = ```Posted at: Mon Mar 29 15:32:53 2010 (GMT) Page 1 of 1

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