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From: sam22Reply 1 of 14Reply         View replies (1)
Subject: Contributed Answer/Explanation to Q. 1
   Rs. 784
   
   Interest For 1st Year = Principal * Rate/100 * Time
   
   
                                    = 5600 *
   14/100 * 1

Posted at: Sun Feb 14 08:46:30 2010 (GMT)

From: sam22Reply 2 of 14Reply
Subject: Contributed Answer/Explanation to Q. 2
   Rs. 6384
   
   Amount = Principal + Interest
   
   
                = 5600 + 784
   
   
                = 6384

Posted at: Sun Feb 14 08:48:38 2010 (GMT)

From: sam22Reply 3 of 14Reply
Subject: Contributed Answer/Explanation to Q. 1
   Rs. 784
   
   Interest For 1st Year = Principal * Rate/100 * Time 
   
   
                                    = 5600 *
   14/100 * 1 
   
   
                                    = 784

Posted at: Sun Feb 14 08:48:54 2010 (GMT)

From: sam22Reply 4 of 14Reply
Subject: Contributed Answer/Explanation to Q. 3
   Rs. 894
   
   Interest For 2nd Year = Principal * Rate/100 * Time
   
   
                                     = 6384 *
   14/100 * 1
   
   
                                     = 893.76
   
   
                                     = 894
   (Correct to the nearest Rs.)

Posted at: Sun Feb 14 08:51:20 2010 (GMT)

From: sam22Reply 5 of 14Reply
Subject: Contributed Answer/Explanation to Q. 4
   Rs. 3500
   
   Selling Price = Marked Price * (1- Discount/100)
   
   
   2975 = M.P. * (1 - 15/100)
   
   
   2975 = M.P. * (85/100)
   
   
   2975 * 100/85 = M.P.
   
   
   Thus, M.P. = 3500

Posted at: Sun Feb 14 08:55:39 2010 (GMT)

From: sam22Reply 6 of 14Reply
Subject: Contributed Answer/Explanation to Q. 5
   Rs. 2500

Posted at: Sun Feb 14 08:57:41 2010 (GMT)

From: sam22Reply 7 of 14Reply
Subject: Contributed Answer/Explanation to Q. 6
   Rs. 475
   
   Profit = Selling Price - Cost Price
   
   
             = 2975 - 2500
   
   
             = 475

Posted at: Sun Feb 14 08:59:41 2010 (GMT)

From: sam22Reply 8 of 14Reply
Subject: Contributed Answer/Explanation to Q. 7
   7.5 km

Posted at: Sun Feb 14 09:03:15 2010 (GMT)

From: sam22Reply 9 of 14Reply
Subject: Contributed Answer/Explanation to Q. 8
   0.0000000006 sq. km.

Posted at: Sun Feb 14 09:45:16 2010 (GMT)

From: sam22Reply 10 of 14Reply
Subject: Contributed Answer/Explanation to Q. 16
   a = 5 & b = 2

Posted at: Sun Feb 14 09:49:56 2010 (GMT)

From: sam22Reply 11 of 14Reply
Subject: Contributed Answer/Explanation to Q. 17
   P(-5,2)

Posted at: Sun Feb 14 09:50:26 2010 (GMT)

From: sam22Reply 12 of 14Reply
Subject: Contributed Answer/Explanation to Q. 19
   PN = 15 cm
   <p>
   In triangle RLQ & triangle PLN,
   </p>
   <p>
   1). Angle RLQ = Angle PLN (Vertically Opp. Angles)
   </p>
   <p>
   2). Angle QRL = Angle NPL (Alternate Angles)
   </p>
   <p>
   Thus, the two triangles are similar. (By A.A. Similarity)
   </p>
   <p>
    
   </p>
   <p>
   Therefore,
   </p>
   <p>
   RL/LP = RQ/PN = QL/LN
   </p>
   <p>
   2/3 = 10/PN
   </p>
   <p>
   PN = (10*3)/2
   </p>
   <p>
   PN= 15 cm
   </p>

Posted at: Sun Feb 14 09:58:55 2010 (GMT)

From: sam22Reply 13 of 14Reply
Subject: Contributed Answer/Explanation to Q. 20
   Triangle QLP is similar to triangle RLM. (RM = 32/3)
   
   RL/LP = RM/PQ = LM/LQ
   
   
   2/3 = RM/16
   
   
   Thus, 
   
   
   RM=32/3

Posted at: Sun Feb 14 10:01:56 2010 (GMT)

From: kp24Reply 14 of 14Reply
Subject: Contributed Answer/Explanation to Q. 1
   784
   Interest for first year =

Posted at: Mon Mar 29 15:32:53 2010 (GMT)

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