Page 1 of 5 > >> |
From: lakhika | Reply 1 of 85 | Reply | |
Subject: Contributed Answer/Explanation to Q. 1 |
hydronium as acid gave out hydronium ions.
Posted at: Sat Feb 20 19:19:07 2010 (GMT)
|
From: lakhika | Reply 2 of 85 | Reply | |
Subject: Contributed Answer/Explanation to Q. 7 |
because metallic increases down a group.
Posted at: Sat Feb 20 19:23:22 2010 (GMT)
|
From: lakhika | Reply 3 of 85 | Reply | |
Subject: Contributed Answer/Explanation to Q. 8 |
bcz electronegativity down a group
Posted at: Sat Feb 20 19:24:47 2010 (GMT)
|
From: lakhika | Reply 4 of 85 | Reply | |
Subject: Contributed Answer/Explanation to Q. 9 |
valence electron remain in a group
Posted at: Sat Feb 20 19:26:19 2010 (GMT)
|
From: alokrajiv | Reply 5 of 85 | Reply | |
Subject: Contributed Answer/Explanation to Q. 56 |
Cation and Anion ( charged particles are asked ) (1/2) each
Posted at: Mon Mar 8 17:36:18 2010 (GMT)
|
From: alokrajiv | Reply 6 of 85 | Reply | View replies (1)
|
Subject: Contributed Answer/Explanation to Q. 61 |
Double bond (only one )
Posted at: Mon Mar 8 17:38:12 2010 (GMT)
|
From: alokrajiv | Reply 7 of 85 | Reply | |
Subject: Contributed Answer/Explanation to Q. 65 |
Triple bond ( a single one )
Posted at: Mon Mar 8 17:39:30 2010 (GMT)
|
From: alokrajiv | Reply 8 of 85 | Reply | View replies (1)
|
Subject: Contributed Answer/Explanation to Q. 70 |
<span style="white-space: nowrap" class="chemf"><a
href="http://en.wikipedia.org/wiki/Hydrogen"
title="Hydrogen">H</a><sub>2</sub></span><span
style="white-space: nowrap" class="chemf"><a
href="http://en.wikipedia.org/wiki/Sulfate"
title="Sulfate">SO<sub>4</sub></a></span>. and
HCl
Posted at: Mon Mar 8 17:47:27 2010 (GMT)
|
From: alokrajiv | Reply 9 of 85 | Reply | |
Subject: Contributed Answer/Explanation to Q. 70 |
<a href="http://en.wikipedia.org/wiki/Hydrogen"
title="Hydrogen"><!--[if gte mso 9]><xml>
<w:WordDocument>
<w:View>Normal</w:View>
<w:Zoom>0</w:Zoom>
<w:Compatibility>
<w:BreakWrappedTables/>
<w:SnapToGridInCell/>
<w:WrapTextWithPunct/>
<w:UseAsianBreakRules/>
</w:Compatibility>
<w:BrowserLevel>MicrosoftInternetExplorer4</w:BrowserLevel>
</w:WordDocument>
</xml><![endif]-->
<!--
/* Style Definitions */
p.MsoNormal, li.MsoNormal, div.MsoNormal
{mso-style-parent:"";
margin:0in;
margin-bottom:.0001pt;
mso-pagination:widow-orphan;
font-size:12.0pt;
font-family:"Times New Roman";
mso-fareast-font-family:"Times New Roman";}
span.chemf
{mso-style-name:chemf;}
@page Section1
{size:595.45pt 841.7pt;
margin:1.0in 27.35pt 1.0in 1.0in;
mso-header-margin:.5in;
mso-footer-margin:.5in;
mso-paper-source:0;}
div.Section1
{page:Section1;}
-->
<!--[if gte mso 10]>
<style>
/* Style Definitions */
table.MsoNormalTable
{mso-style-name:"Table Normal";
mso-tstyle-rowband-size:0;
mso-tstyle-colband-size:0;
mso-style-noshow:yes;
mso-style-parent:"";
mso-padding-alt:0in 5.4pt 0in 5.4pt;
mso-para-margin:0in;
mso-para-margin-bottom:.0001pt;
mso-pagination:widow-orphan;
font-size:10.0pt;
font-family:"Times New Roman";}
</style>
<![endif]-->
</a>
<!--
/* Style Definitions */
p.MsoNormal, li.MsoNormal, div.MsoNormal
{mso-style-parent:"";
margin:0in;
margin-bottom:.0001pt;
mso-pagination:widow-orphan;
font-size:12.0pt;
font-family:"Times New Roman";
mso-fareast-font-family:"Times New Roman";}
span.chemf
{mso-style-name:chemf;}
@page Section1
{size:595.45pt 841.7pt;
margin:1.0in 27.35pt 1.0in 1.0in;
mso-header-margin:.5in;
mso-footer-margin:.5in;
mso-paper-source:0;}
div.Section1
{page:Section1;}
-->
<!--[if gte mso 10]>
<style>
/* Style Definitions */
table.MsoNormalTable
{mso-style-name:"Table Normal";
mso-tstyle-rowband-size:0;
mso-tstyle-colband-size:0;
mso-style-noshow:yes;
mso-style-parent:"";
mso-padding-alt:0in 5.4pt 0in 5.4pt;
mso-para-margin:0in;
mso-para-margin-bottom:.0001pt;
mso-pagination:widow-orphan;
font-size:10.0pt;
font-family:"Times New Roman";}
</style>
<![endif]-->
<p class="MsoNormal">
<span class="chemf">H<sub>2</sub>SO<sub>4
</sub></span><span class="chemf"> and
</span><span class="chemf">HCl<br />
</span>
</p>
Posted at: Mon Mar 8 17:51:35 2010 (GMT)
|
From: alokrajiv | Reply 10 of 85 | Reply | |
Subject: Contributed Answer/Explanation to Q. 72 |
The colour of litmus present after the expirement is noted. If it is blue it
was Ammonia, else if it was red it was Hydrogen chloride.
Posted at: Mon Mar 8 17:54:00 2010 (GMT)
|
From: alokrajiv | Reply 11 of 85 | Reply | View replies (2)
|
Subject: Contributed Answer/Explanation to Q. 73 |
<p>
<span style="white-space: nowrap" class="chemf">Fe + 2HCl
→ FeCl<sub>2</sub> + H<sub>2</sub></span>
</p>
<p>
With HCl, metals with variable valency forms always lower chloride.
</p>
Posted at: Mon Mar 8 17:59:17 2010 (GMT)
|
From: alokrajiv | Reply 12 of 85 | Reply | |
Subject: Contributed Answer/Explanation to Q. 73 |
<p>
<span style="white-space: nowrap" class="chemf">Fe + 2HCl
→ FeCl<sub>2</sub> + H<sub>2</sub></span>
</p>
<p>
With HCl, metals with variable valency forms always lower chlorides.
</p>
Posted at: Mon Mar 8 18:03:26 2010 (GMT)
|
From: alokrajiv | Reply 13 of 85 | Reply | |
Subject: Contributed Answer/Explanation to Q. 73 |
<p>
<span style="white-space: nowrap" class="chemf">Fe + 2HCl
→ FeCl<sub>2</sub> + H<sub>2</sub></span>
</p>
<p>
With HCl, metals with variable valency forms always lower chlorides.
</p>
Posted at: Mon Mar 8 18:04:18 2010 (GMT)
|
From: alokrajiv | Reply 14 of 85 | Reply | |
Subject: Contributed Answer/Explanation to Q. 73 |
<p>
<span style="white-space: nowrap" class="chemf">Fe + 2HCl
→ FeCl<sub>2</sub> + H<sub>2</sub></span>
</p>
<p>
With HCl, metals with variable valency forms always lower chlorides.
</p>
Posted at: Mon Mar 8 18:04:44 2010 (GMT)
|
From: alokrajiv | Reply 15 of 85 | Reply | View replies (2)
|
Subject: Contributed Answer/Explanation to Q. 77 |
Na2S2O3 + HCl → NaCl + SO2 + H2O + S
Posted at: Mon Mar 8 18:10:59 2010 (GMT)
|
From: alokrajiv | Reply 16 of 85 | Reply | |
Subject: Contributed Answer/Explanation to Q. 77 |
Na2S2O3 + HCl → NaCl + SO2 + H2O + S
( Simpler, accepted in key )
Posted at: Mon Mar 8 18:11:29 2010 (GMT)
|
From: alokrajiv | Reply 17 of 85 | Reply | |
Subject: Contributed Answer/Explanation to Q. 77 |
Na2S2O3 + HCl → NaCl + SO2 + H2O + S
( Simpler, and accepted in key )
Posted at: Mon Mar 8 18:11:46 2010 (GMT)
|
From: alokrajiv | Reply 18 of 85 | Reply | |
Subject: Contributed Answer/Explanation to Q. 77 |
Na2S2O3 + HCl → NaCl + SO2 +
H2O + S
( Simpler, and accepted in key )
Posted at: Mon Mar 8 18:12:04 2010 (GMT)
|
From: kaustubh_mokashi | Reply 19 of 85 | Reply | |
Subject: Contributed Answer/Explanation to Q. 1 |
H3O+
Posted at: Tue Mar 9 08:24:17 2010 (GMT)
|
From: kaustubh_mokashi | Reply 20 of 85 | Reply | |
Subject: Contributed Answer/Explanation to Q. 2 |
OH -
Posted at: Tue Mar 9 08:24:58 2010 (GMT)
|
Page 1 of 5 > >> |