| Page 1 of 3 > >> |
| From: shiwangi | Reply 1 of 51 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 7 |
chlorine
Posted at: Sun Feb 21 20:38:31 2010 (GMT)
|
| From: tanmay_3394 | Reply 2 of 51 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 34 |
A is Anode and B is Cathode
Posted at: Wed Feb 24 07:37:35 2010 (GMT)
|
| From: tanmay_3394 | Reply 3 of 51 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 43 |
Ammonia
Posted at: Wed Feb 24 07:40:16 2010 (GMT)
|
| From: alokrajiv | Reply 4 of 51 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 15 |
Calcium silicate ( Formulae are not often accepted )
Posted at: Tue Mar 9 04:24:46 2010 (GMT)
|
| From: alokrajiv | Reply 5 of 51 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 29 |
Blue colour of Solution fades
Reddish brown deposit at the cathode
Posted at: Tue Mar 9 04:54:03 2010 (GMT)
|
| From: alokrajiv | Reply 6 of 51 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 30 |
Curdy white ppt observed
Posted at: Tue Mar 9 04:55:18 2010 (GMT)
|
| From: alokrajiv | Reply 7 of 51 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 31 |
Bromine water is decolourised
Posted at: Tue Mar 9 04:55:55 2010 (GMT)
|
| From: moosa | Reply 8 of 51 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 32 |
Brown colour fades to a yellow colour
Reddish brown vapour in the bottle
Posted at: Tue Mar 9 04:58:03 2010 (GMT)
|
| From: alokrajiv | Reply 9 of 51 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 32 |
The acid gains a brownish yellow colour.
Reddish brown vapours are seen in the bottle.
Posted at: Tue Mar 9 04:59:44 2010 (GMT)
|
| From: alokrajiv | Reply 10 of 51 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 33 |
White ppt
Dissolves in excess
Posted at: Tue Mar 9 05:02:14 2010 (GMT)
|
| From: alokrajiv | Reply 11 of 51 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 35 |
Anode (A)
Posted at: Tue Mar 9 05:09:51 2010 (GMT)
|
| From: rsp9099 | Reply 12 of 51 | Reply | View replies (1)
|
| Subject: Contributed Answer/Explanation to Q. 37 |
Number of electrons gained by the cathode must be equal to the number of
electrons lost by the cahode.
At Cathode,
4H+ + 4e- --> 4H
2H + 2H -->2H2
At Anode,
4OH - - 4e- --> 4OH
2OH + 2OH -->2H2O + 2O
O + O -->O2
Posted at: Tue Mar 9 15:12:07 2010 (GMT)
|
| From: rsp9099 | Reply 13 of 51 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 37 |
Number of electrons gained by the cathode must be equal to the number of
electrons lost by the anode.
At Cathode,
4H+ + 4e- --> 4H
2H + 2H -->2H2
At Anode,
4OH - - 4e- --> 4OH
2OH + 2OH -->2H2O + 2O
O + O -->O2
Posted at: Tue Mar 9 15:12:21 2010 (GMT)
|
| From: rsp9099 | Reply 14 of 51 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 48 |
<p>
Only equation not equations.......
</p>
<p>
<.<
</p>
<p>
</p>
<p>
CH<sub>4 </sub>+ 4Cl<sub>2</sub> -->
CCl<sub>4</sub> + 4HCl
</p>
Posted at: Tue Mar 9 15:18:18 2010 (GMT)
|
| From: rsp9099 | Reply 15 of 51 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 51 |
homologous
Posted at: Tue Mar 9 15:19:01 2010 (GMT)
|
| From: rsp9099 | Reply 16 of 51 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 52 |
unsaturated
Posted at: Tue Mar 9 15:19:22 2010 (GMT)
|
| From: rsp9099 | Reply 17 of 51 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 53 |
double
Posted at: Tue Mar 9 15:19:37 2010 (GMT)
|
| From: rsp9099 | Reply 18 of 51 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 54 |
addition
Posted at: Tue Mar 9 15:19:52 2010 (GMT)
|
| From: rsp9099 | Reply 19 of 51 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 55 |
Nitric acid is highly corrosive
Posted at: Tue Mar 9 15:20:21 2010 (GMT)
|
| From: rsp9099 | Reply 20 of 51 | Reply | View replies (1)
|
| Subject: Contributed Answer/Explanation to Q. 65 |
Its CarbonMonoxide
3CO+Fe2O3-->3CO2+Fe
Posted at: Tue Mar 9 15:25:55 2010 (GMT)
|
| Page 1 of 3 > >> |
