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From: raydzhaoReply 1 of 1Reply
Subject: i disagree with the answer of this question
   it should be 1 less than whatever the algorithm produces. here is my
   solution, assume dollar amount is X
   The largest bag should have X/2 rounded up to the nearest dollar, the second
   largest bag should be at least half of the remaining amount, and so on...
   to prove it, look at it from bottom up: the last bag must have 1, and second
   last bag have 2... its too much to type in this text box, think about it...

Posted at: Fri Apr 3 02:52:31 2009 (GMT)

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