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SCIENCE
Paper 2 (Chemistry) - 2004
(One hour and a half)

Question 1
(b) When heated, potassium permanganate decomposes according to the following equation

2KMnO4→K2MnO4+ MnO2 + O2

Solid residue



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7.

(i) Some potassium permanganate was heated in a test tube. After collecting one litre of oxygen at room temperature it was found that the test-tube had undergone a loss in mass of 1.32 g. If one litre of hydrogen under the same conditions of temperature and pressure has a mass of 0.0825 g, calculate the relative molecular mass of oxygen.
 

8.

(ii) Given that the molecular mass of potassium permanganate is 158, what volume of oxygen (measured at room temperature) would be obtained by the complete decomposition of 15.8 g of potassium permanganate?
(Molar volume at room temperature is 24 litres.)
 


 
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