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Algebraic Expressions - Evaluation 3

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Find the value of the algebraic expression by substituting the given value of the variable.

1. k + 31.3 where k = 34.2
Answer: 65.5
313 + 342 = 655
There is 1 decimal place in the numbers being added.
So the sum must have 1 decimal place.
Thus, 31.3 + 34.2 = 65.5


2. t + 36.0 where t = 22.9
Answer: 58.9
360 + 229 = 589
There is 1 decimal place in the numbers being added.
So the sum must have 1 decimal place.
Thus, 36.0 + 22.9 = 58.9


3. 7.09 + f where f = 2.80
Answer: 9.89
709 + 280 = 989
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 7.09 + 2.80 = 9.89



4. 19.24 + g where g = 13.80
Answer: 33.04
1924 + 1380 = 3304
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 19.24 + 13.80 = 33.04


5. 43.14 + d where d = 13.43
Answer: 56.57
4314 + 1343 = 5657
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 43.14 + 13.43 = 56.57


6. g − 6.3 where g = 12.4
Answer: 6.1
124 − 63 = 61
There is 1 decimal place in the numbers being subtracted.
So the difference must have 1 decimal place.
Thus, 12.4 − 6.3 = 6.1


7. k − 7.4 where k = 15.0
Answer: 7.6
150 − 74 = 76
There is 1 decimal place in the numbers being subtracted.
So the difference must have 1 decimal place.
Thus, 15.0 − 7.4 = 7.6


8. 14.06 − a where a = 9.26
Answer: 4.80
1406 − 926 = 480
There are 2 decimal places in the numbers being subtracted.
So the difference must have 2 decimal places.
Thus, 14.06 − 9.26 = 4.80


9. 17.76 − h where h = 13.13
Answer: 4.63
1776 − 1313 = 463
There are 2 decimal places in the numbers being subtracted.
So the difference must have 2 decimal places.
Thus, 17.76 − 13.13 = 4.63


10. r × 0.5 where r = 1.4
Answer: 0.70
5 × 14 = 70
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 0.5 × 1.4 = 0.70


11. 0.2 × j where j = 4
Answer: 0.8
2 × 4 = 8
There is 1 decimal place in the multiplicand and 0 in the multiplier.
So the product must have 1 + 0 = 1 decimal place.
Thus, 0.2 × 4 = 0.8


12. g × 4.1 where g = 5.5
Answer: 22.55
55 × 41 = 2255
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 5.5 × 4.1 = 22.55


13. m × 4.8 where m = 8.2
Answer: 39.36
82 × 48 = 3936
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 8.2 × 4.8 = 39.36


14. 0.79 × e where e = 8
Answer: 6.32
79 × 8 = 632
There are 2 decimal places in the multiplicand and 0 in the multiplier.
So the product must have 2 + 0 = 2 decimal places.
Thus, 0.79 × 8 = 6.32


15. q ÷ 0.7 where q = 1.61
Answer: 2.3
16.1 ÷ 7 [Multiplied divisor and dividend by 10]
Now, 161 ÷ 7  
= 23 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 1.61 ÷ 0.7 = 2.3


16. q ÷ 0.3 where q = 0.93
Answer: 3.1
9.3 ÷ 3 [Multiplied divisor and dividend by 10]
Now, 93 ÷ 3  
= 31 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 0.93 ÷ 0.3 = 3.1


17. q ÷ 0.8 where q = 12
Answer: 15
120 ÷ 8  [Multiplied divisor and dividend by 10]
Now, 120 ÷ 8
= 15 There is 0 decimal place in thedividend so the quotient must have 0 decimal place.
Thus, 12 ÷ 0.8 = 15


18. w ÷ 0.4 where w = 8
Answer: 21
84 ÷ 4  [Multiplied divisor and dividend by 10]
Now, 84 ÷ 4
= 21 There is 0 decimal place in thedividend so the quotient must have 0 decimal place.
Thus, 8 ÷ 0.4 = 21


19. g ÷ 2.6 where g = 23.40
Answer: 9.0
234.0 ÷ 26 [Multiplied divisor and dividend by 10]
Now, 2340 ÷ 26  
= 90 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 23.40 ÷ 2.6 = 9.0


20. y ÷ 1.3 where y = 16.64
Answer: 12.8
166.4 ÷ 13 [Multiplied divisor and dividend by 10]
Now, 1664 ÷ 13  
= 128 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 16.64 ÷ 1.3 = 12.8



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