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| Find the value of the algebraic expression by substituting the given value of the variable. |
1. k + 16.8 where k = 44.9
Answer: 61.7168 + 449 = 617
There is 1 decimal place in the numbers being added.
So the sum must have 1 decimal place.
Thus, 16.8 + 44.9 = 61.7
2. t + 37.2 where t = 23.4
Answer: 60.6372 + 234 = 606
There is 1 decimal place in the numbers being added.
So the sum must have 1 decimal place.
Thus, 37.2 + 23.4 = 60.6
3. 6.52 + f where f = 2.25
Answer: 8.77652 + 225 = 877
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 6.52 + 2.25 = 8.77
4. 25.23 + g where g = 10.67
Answer: 35.902523 + 1067 = 3590
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 25.23 + 10.67 = 35.90
5. 27.03 + d where d = 16.24
Answer: 43.272703 + 1624 = 4327
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 27.03 + 16.24 = 43.27
6. g − 4.1 where g = 11.6
Answer: 7.5116 − 41 = 75
There is 1 decimal place in the numbers being subtracted.
So the difference must have 1 decimal place.
Thus, 11.6 − 4.1 = 7.5
7. k − 5.4 where k = 11.8
Answer: 6.4118 − 54 = 64
There is 1 decimal place in the numbers being subtracted.
So the difference must have 1 decimal place.
Thus, 11.8 − 5.4 = 6.4
8. 12.64 − a where a = 6.48
Answer: 6.161264 − 648 = 616
There are 2 decimal places in the numbers being subtracted.
So the difference must have 2 decimal places.
Thus, 12.64 − 6.48 = 6.16
9. 17.99 − h where h = 10.36
Answer: 7.631799 − 1036 = 763
There are 2 decimal places in the numbers being subtracted.
So the difference must have 2 decimal places.
Thus, 17.99 − 10.36 = 7.63
10. r × 0.6 where r = 1.6
Answer: 0.966 × 16 = 96
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 0.6 × 1.6 = 0.96
11. 0.6 × j where j = 9
Answer: 5.46 × 9 = 54
There is 1 decimal place in the multiplicand and 0 in the multiplier.
So the product must have 1 + 0 = 1 decimal place.
Thus, 0.6 × 9 = 5.4
12. g × 3.7 where g = 5.4
Answer: 19.9854 × 37 = 1998
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 5.4 × 3.7 = 19.98
13. m × 5.0 where m = 7.0
Answer: 35.0070 × 50 = 3500
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 7.0 × 5.0 = 35.00
14. 0.72 × e where e = 9
Answer: 6.4872 × 9 = 648
There are 2 decimal places in the multiplicand and 0 in the multiplier.
So the product must have 2 + 0 = 2 decimal places.
Thus, 0.72 × 9 = 6.48
15. q ÷ 0.8 where q = 2.48
Answer: 3.124.8 ÷ 8 [Multiplied divisor and dividend by 10]
Now, 248 ÷ 8
= 31 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 2.48 ÷ 0.8 = 3.1
16. q ÷ 0.3 where q = 0.60
Answer: 2.06.0 ÷ 3 [Multiplied divisor and dividend by 10]
Now, 60 ÷ 3
= 20 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 0.60 ÷ 0.3 = 2.0
17. q ÷ 0.3 where q = 4
Answer: 1442 ÷ 3 [Multiplied divisor and dividend by 10]
Now, 42 ÷ 3
= 14 There is 0 decimal place in thedividend so the quotient must have 0 decimal place.
Thus, 4 ÷ 0.3 = 14
18. w ÷ 0.6 where w = 19
Answer: 32192 ÷ 6 [Multiplied divisor and dividend by 10]
Now, 192 ÷ 6
= 32 There is 0 decimal place in thedividend so the quotient must have 0 decimal place.
Thus, 19 ÷ 0.6 = 32
19. g ÷ 3.3 where g = 34.98
Answer: 10.6349.8 ÷ 33 [Multiplied divisor and dividend by 10]
Now, 3498 ÷ 33
= 106 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 34.98 ÷ 3.3 = 10.6
20. y ÷ 1.3 where y = 15.34
Answer: 11.8153.4 ÷ 13 [Multiplied divisor and dividend by 10]
Now, 1534 ÷ 13
= 118 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 15.34 ÷ 1.3 = 11.8
Try the Quiz : Algebraic Expressions - Evaluation 3
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