Hide all answers
Hide all answers
View all answers
View all answers
Print
Try the Quiz
Find the value of the algebraic expression by substituting the given value of the variable. 
1. k + 20.3 where k = 10.3 Answer: 30.6203 + 103 = 306
There is 1 decimal place in the numbers being added.
So the sum must have 1 decimal place.
Thus, 20.3 + 10.3 = 30.6
2. t + 36.8 where t = 22.5 Answer: 59.3368 + 225 = 593
There is 1 decimal place in the numbers being added.
So the sum must have 1 decimal place.
Thus, 36.8 + 22.5 = 59.3
3. 6.65 + f where f = 1.58 Answer: 8.23665 + 158 = 823
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 6.65 + 1.58 = 8.23
4. 24.18 + g where g = 14.37 Answer: 38.552418 + 1437 = 3855
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 24.18 + 14.37 = 38.55
5. 34.20 + d where d = 13.32 Answer: 47.523420 + 1332 = 4752
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 34.20 + 13.32 = 47.52
6. g − 6.5 where g = 11.8 Answer: 5.3118 − 65 = 53
There is 1 decimal place in the numbers being subtracted.
So the difference must have 1 decimal place.
Thus, 11.8 − 6.5 = 5.3
7. k − 3.5 where k = 14.6 Answer: 11.1146 − 35 = 111
There is 1 decimal place in the numbers being subtracted.
So the difference must have 1 decimal place.
Thus, 14.6 − 3.5 = 11.1
8. 12.68 − a where a = 7.31 Answer: 5.371268 − 731 = 537
There are 2 decimal places in the numbers being subtracted.
So the difference must have 2 decimal places.
Thus, 12.68 − 7.31 = 5.37
9. 16.11 − h where h = 12.26 Answer: 3.851611 − 1226 = 385
There are 2 decimal places in the numbers being subtracted.
So the difference must have 2 decimal places.
Thus, 16.11 − 12.26 = 3.85
10. r × 0.3 where r = 1.5 Answer: 0.453 × 15 = 45
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 0.3 × 1.5 = 0.45
11. 0.6 × j where j = 7 Answer: 4.26 × 7 = 42
There is 1 decimal place in the multiplicand and 0 in the multiplier.
So the product must have 1 + 0 = 1 decimal place.
Thus, 0.6 × 7 = 4.2
12. g × 3.3 where g = 5.7 Answer: 18.8157 × 33 = 1881
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 5.7 × 3.3 = 18.81
13. m × 5.2 where m = 9.2 Answer: 47.8492 × 52 = 4784
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 9.2 × 5.2 = 47.84
14. 0.50 × e where e = 5 Answer: 2.5050 × 5 = 250
There are 2 decimal places in the multiplicand and 0 in the multiplier.
So the product must have 2 + 0 = 2 decimal places.
Thus, 0.50 × 5 = 2.50
15. q ÷ 0.2 where q = 0.42 Answer: 2.14.2 ÷ 2 [Multiplied divisor and dividend by 10]
Now, 42 ÷ 2
= 21 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 0.42 ÷ 0.2 = 2.1
16. q ÷ 0.6 where q = 2.04 Answer: 3.420.4 ÷ 6 [Multiplied divisor and dividend by 10]
Now, 204 ÷ 6
= 34 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 2.04 ÷ 0.6 = 3.4
17. q ÷ 0.3 where q = 3 Answer: 1236 ÷ 3 [Multiplied divisor and dividend by 10]
Now, 36 ÷ 3
= 12 There is 0 decimal place in thedividend so the quotient must have 0 decimal place.
Thus, 3 ÷ 0.3 = 12
18. w ÷ 0.3 where w = 9 Answer: 3090 ÷ 3 [Multiplied divisor and dividend by 10]
Now, 90 ÷ 3
= 30 There is 0 decimal place in thedividend so the quotient must have 0 decimal place.
Thus, 9 ÷ 0.3 = 30
19. g ÷ 3.5 where g = 38.85 Answer: 11.1388.5 ÷ 35 [Multiplied divisor and dividend by 10]
Now, 3885 ÷ 35
= 111 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 38.85 ÷ 3.5 = 11.1
20. y ÷ 2.5 where y = 29.75 Answer: 11.9297.5 ÷ 25 [Multiplied divisor and dividend by 10]
Now, 2975 ÷ 25
= 119 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 29.75 ÷ 2.5 = 11.9
Try the Quiz : Algebraic Expressions  Evaluation 3
