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## Algebraic Expressions - Evaluation 3

 Formats Info Page Worksheet / Test Paper Quiz Review

 Find the value of the algebraic expression by substituting the given value of the variable.

1. k + 43.0 where k = 49.7
430 + 497 = 927
There is 1 decimal place in the numbers being added.
So the sum must have 1 decimal place.
Thus, 43.0 + 49.7 = 92.7

2. t + 41.3 where t = 24.2
413 + 242 = 655
There is 1 decimal place in the numbers being added.
So the sum must have 1 decimal place.
Thus, 41.3 + 24.2 = 65.5

3. 6.43 + f where f = 2.68
643 + 268 = 911
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 6.43 + 2.68 = 9.11

4. 22.61 + g where g = 14.78
2261 + 1478 = 3739
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 22.61 + 14.78 = 37.39

5. 41.75 + d where d = 20.17
4175 + 2017 = 6192
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 41.75 + 20.17 = 61.92

6. g − 5.7 where g = 10.1
101 − 57 = 44
There is 1 decimal place in the numbers being subtracted.
So the difference must have 1 decimal place.
Thus, 10.1 − 5.7 = 4.4

7. k − 4.4 where k = 13.3
133 − 44 = 89
There is 1 decimal place in the numbers being subtracted.
So the difference must have 1 decimal place.
Thus, 13.3 − 4.4 = 8.9

8. 14.35 − a where a = 7.63
1435 − 763 = 672
There are 2 decimal places in the numbers being subtracted.
So the difference must have 2 decimal places.
Thus, 14.35 − 7.63 = 6.72

9. 16.90 − h where h = 13.14
1690 − 1314 = 376
There are 2 decimal places in the numbers being subtracted.
So the difference must have 2 decimal places.
Thus, 16.90 − 13.14 = 3.76

10. r × 0.8 where r = 1.8
8 × 18 = 144
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 0.8 × 1.8 = 1.44

11. 0.4 × j where j = 4
4 × 4 = 16
There is 1 decimal place in the multiplicand and 0 in the multiplier.
So the product must have 1 + 0 = 1 decimal place.
Thus, 0.4 × 4 = 1.6

12. g × 3.6 where g = 5.2
52 × 36 = 1872
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 5.2 × 3.6 = 18.72

13. m × 5.0 where m = 9.4
94 × 50 = 4700
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 9.4 × 5.0 = 47.00

14. 0.85 × e where e = 7
85 × 7 = 595
There are 2 decimal places in the multiplicand and 0 in the multiplier.
So the product must have 2 + 0 = 2 decimal places.
Thus, 0.85 × 7 = 5.95

15. q ÷ 0.8 where q = 2.00
20.0 ÷ 8 [Multiplied divisor and dividend by 10]
Now, 200 ÷ 8
= 25 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 2.00 ÷ 0.8 = 2.5

16. q ÷ 0.2 where q = 0.44
4.4 ÷ 2 [Multiplied divisor and dividend by 10]
Now, 44 ÷ 2
= 22 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 0.44 ÷ 0.2 = 2.2

17. q ÷ 0.3 where q = 4
48 ÷ 3  [Multiplied divisor and dividend by 10]
Now, 48 ÷ 3
= 16 There is 0 decimal place in thedividend so the quotient must have 0 decimal place.
Thus, 4 ÷ 0.3 = 16

18. w ÷ 0.3 where w = 6
66 ÷ 3  [Multiplied divisor and dividend by 10]
Now, 66 ÷ 3
= 22 There is 0 decimal place in thedividend so the quotient must have 0 decimal place.
Thus, 6 ÷ 0.3 = 22

19. g ÷ 3.8 where g = 42.94
429.4 ÷ 38 [Multiplied divisor and dividend by 10]
Now, 4294 ÷ 38
= 113 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 42.94 ÷ 3.8 = 11.3

20. y ÷ 2.3 where y = 29.44