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| Find the value of the algebraic expression by substituting the given value of the variable. |
1. k + 15.8 where k = 20.3
Answer: 36.1158 + 203 = 361
There is 1 decimal place in the numbers being added.
So the sum must have 1 decimal place.
Thus, 15.8 + 20.3 = 36.1
2. t + 34.8 where t = 21.0
Answer: 55.8348 + 210 = 558
There is 1 decimal place in the numbers being added.
So the sum must have 1 decimal place.
Thus, 34.8 + 21.0 = 55.8
3. 6.05 + f where f = 1.62
Answer: 7.67605 + 162 = 767
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 6.05 + 1.62 = 7.67
4. 20.27 + g where g = 14.42
Answer: 34.692027 + 1442 = 3469
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 20.27 + 14.42 = 34.69
5. 40.52 + d where d = 18.99
Answer: 59.514052 + 1899 = 5951
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 40.52 + 18.99 = 59.51
6. g − 7.6 where g = 11.9
Answer: 4.3119 − 76 = 43
There is 1 decimal place in the numbers being subtracted.
So the difference must have 1 decimal place.
Thus, 11.9 − 7.6 = 4.3
7. k − 4.4 where k = 11.4
Answer: 7.0114 − 44 = 70
There is 1 decimal place in the numbers being subtracted.
So the difference must have 1 decimal place.
Thus, 11.4 − 4.4 = 7.0
8. 13.56 − a where a = 9.53
Answer: 4.031356 − 953 = 403
There are 2 decimal places in the numbers being subtracted.
So the difference must have 2 decimal places.
Thus, 13.56 − 9.53 = 4.03
9. 18.77 − h where h = 11.61
Answer: 7.161877 − 1161 = 716
There are 2 decimal places in the numbers being subtracted.
So the difference must have 2 decimal places.
Thus, 18.77 − 11.61 = 7.16
10. r × 0.3 where r = 1.4
Answer: 0.423 × 14 = 42
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 0.3 × 1.4 = 0.42
11. 0.6 × j where j = 11
Answer: 6.66 × 11 = 66
There is 1 decimal place in the multiplicand and 0 in the multiplier.
So the product must have 1 + 0 = 1 decimal place.
Thus, 0.6 × 11 = 6.6
12. g × 2.3 where g = 5.7
Answer: 13.1157 × 23 = 1311
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 5.7 × 2.3 = 13.11
13. m × 4.5 where m = 6.9
Answer: 31.0569 × 45 = 3105
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 6.9 × 4.5 = 31.05
14. 0.43 × e where e = 2
Answer: 0.8643 × 2 = 86
There are 2 decimal places in the multiplicand and 0 in the multiplier.
So the product must have 2 + 0 = 2 decimal places.
Thus, 0.43 × 2 = 0.86
15. q ÷ 0.2 where q = 0.66
Answer: 3.36.6 ÷ 2 [Multiplied divisor and dividend by 10]
Now, 66 ÷ 2
= 33 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 0.66 ÷ 0.2 = 3.3
16. q ÷ 0.4 where q = 1.00
Answer: 2.510.0 ÷ 4 [Multiplied divisor and dividend by 10]
Now, 100 ÷ 4
= 25 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 1.00 ÷ 0.4 = 2.5
17. q ÷ 0.8 where q = 11
Answer: 14112 ÷ 8 [Multiplied divisor and dividend by 10]
Now, 112 ÷ 8
= 14 There is 0 decimal place in thedividend so the quotient must have 0 decimal place.
Thus, 11 ÷ 0.8 = 14
18. w ÷ 0.4 where w = 8
Answer: 2184 ÷ 4 [Multiplied divisor and dividend by 10]
Now, 84 ÷ 4
= 21 There is 0 decimal place in thedividend so the quotient must have 0 decimal place.
Thus, 8 ÷ 0.4 = 21
19. g ÷ 2.7 where g = 25.11
Answer: 9.3251.1 ÷ 27 [Multiplied divisor and dividend by 10]
Now, 2511 ÷ 27
= 93 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 25.11 ÷ 2.7 = 9.3
20. y ÷ 1.8 where y = 20.70
Answer: 11.5207.0 ÷ 18 [Multiplied divisor and dividend by 10]
Now, 2070 ÷ 18
= 115 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 20.70 ÷ 1.8 = 11.5
Try the Quiz : Algebraic Expressions - Evaluation 3
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