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Algebraic Expressions - Formulation

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Select the algebraic expression(s) to represent the word problem(s).

1. Bill bought t marbles. Robin bought 27 marbles less than Bill. How many marbles did Robin buy?
t + 27
t − 27
• 27
• 27 − t
Answer: t − 27
Marbles Bill bought = t
Marbles Robin bought = t − 27
'27 less than t' is equivalent to 't − 27' in symbols.


2. Kathleen bought f pencils. Pamela bought 15 pencils more than Kathleen. How many pencils did Pamela buy?
f − 15
• 15
f  + 15
• 15 − f
Answer: f  + 15
Pencils Kathleen bought = f
Pencils Pamela bought = f  + 15
'15 more than f' is equivalent to 'f  + 15' in symbols.


3. Kathleen lost 9 marbles. She had g marbles. How many marbles does Kathleen have now?
g + 9
• 9
• 9 − g
g − 9
Answer: g − 9
Marbles Kathleen had = g
Marbles Kathleen lost = 9
Marbles Kathleen has now = g − 9
'lost 9 from g' is equivalent to 'g − 9' in symbols.



4. Bill borrowed 11 golf balls from Robin. Robin had d golf balls. How many golf balls does Robin have now?
d + 11
d − 11
• 11
• 11 − d
Answer: d − 11
Golf balls Robin had = d
Golf balls Bill borrowed = 11
Golf balls Robin has now = d − 11
'borrowed 11 from d' is equivalent to 'd − 11' in symbols.


5. Kathleen scored 9 extra credit points than Robin. Robin scored h credit points. How many credit points did Kathleen score?
• 9 − h
h + 9
h
h − 9
Answer: h + 9
Points Pamela scored = h
Points Kathleen scored = h + 9
'9 extra than h' is equivalent to 'h + 9' in symbols.


6. Bill scored 9 fewer credit points than Robin. Robin scored p credit points. How many credit points did Bill score?
p − 9
p + 9
• 9
• 9 − p
Answer: p − 9
Points Robin scored = p
Points Bill scored = p − 9
'9 fewer than p' is equivalent to 'p − 9' in symbols.


7. There were 26 dolls in a box. k dolls were taken away. How many dolls are left in the box now?
k + 26
• 26 − k
• 26
k − 26
Answer: 26 − k
Dolls in a box = 26
Dolls taken away = k
Dolls left = 26 − k
'k taken away from 26' is equivalent to '26 − k' in symbols.


8. There were 21 dolls in a box. h new dolls were added to the box. How many dolls are present in the box now?
• 21 − h
• 21
• 21 + h
h − 21
Answer: 21 + h
Dolls in a box = 21
Dolls added = h
Dolls present now = 21 + h
'added h to 21' is equivalent to '21 + h' in symbols.


9. There are 9 big boxes and x small boxes. What is the total number of boxes?
• 9 + x
• 9 − x
• 9
x − 9
Answer: 9 + x
Big boxes = 9
Small boxes = x
Total boxes = 9 + x
'total of 9 and x' is equivalent to '9 + x' in symbols.


10. Bill has y red jelly beans and 15 blue jelly beans. What is the total number of jelly beans?
y − 15
• 15
• 15 − y
y + 15
Answer: y + 15
Red jelly beans = y
Blue jelly beans = 15
Total jelly beans = y +15
'total of y and 15' is equivalent to 'y +15' in symbols.


11. Kathleen ate t more cookies than Robin. Robin ate 6 cookies. How many cookies did Kathleen eat?
t + 6
t − 6
t
• 6 − t
Answer: t + 6
Cookies Pamela ate = 6
Cookies Kathleen ate = t + 6
't more than 6' is equivalent to 't + 6' in symbols.


12. Kathleen ate 4 fewer cookies than Pamela. Pamela ate k cookies. How many cookies did Kathleen eat?
• 4 − k
k
k + 4
k − 4
Answer: k − 4
Cookies Pamela ate = k
Cookies Kathleen ate = k − 4
'4 fewer than k' is equivalent to 'k − 4' in symbols.


13. Kathleen is 5 years younger than her sister. Kathleen's sister is b years old. What is Kathleen's age?
• 5 − b
b − 5
5
b + 5
Answer: b − 5
Kathleen's sister's age = b
Kathleen age = b − 5
'5 years younger than b' is equivalent to 'b − 5' in symbols.


14. Bill is j years younger than his sister. Bill's sister is 18 years old. What is Bill's age?
j − 18
j
j + 18
• 18 − j
Answer: 18 − j
Bill's sister's age = 18
Bill age = 18 − j
'j years younger than 18' is equivalent to '18 − j' in symbols.


15. Bill's brother is r years older than him. Bill is 25 years old. What is Bill's brother's age?
• 25 + r
r − 25
r
• 25 − r
Answer: 25 + r
Bill's age = r
Bill's brother's age = 25 + r
'r years older than 25' is equivalent to '25 + r' in symbols.


16. Bill and Pamela painted f pictures each. Ronald painted 12 pictures more than Bill. How many pictures did Ronald paint?
f + 12
f − 12
• 12
• 12 − f
Answer: f + 12
Pictures Bill painted = f
Pictures Ronald painted = f +12
'12 more than f' is equivalent to 'f + 12' in symbols.


17. There are 27 toy cars in a store. d toy cars are sold. How many toy cars are left in the store?
• 27 − d
d − 27
d
• 27 + d
Answer: 27 − d
Toy cars in a store = 27
Toy cars sold =d
Toy cars left = 27 − d
'sold d from 27' is equivalent to '27 − d' in symbols.


18. Kathleen had 8 books. Robin gave her g more books. Kathleen then bought 3 new books. What is the total number of books Kathleen has?
g + 8
g + 3
g + 11
g − 11
Answer: g + 11
Books Kathleen had = 8
Books Pamela gave Kathleen = g
Books Kathleen bought = 3
Total books Kathleen has = g + 8 + 3 = g + 11
'total of g and 8 and 3' is equivalent to ' g + 11' in symbols.


19. Bill had t crayons. Pamela borrowed 3 crayons from Bill. Pamela then borrowed 11 more crayons from Bill. How many crayons does Bill have now?
t − 3
t − 14
t − 11
t + 11
Answer: t − 14
Crayons Bill had = t
Crayons Robin borrowed = 3 + 11 = 14
Crayons Bill has now = t − 14
'borrowed 14 from t' is equivalent to ' t − 14' in symbols.


20. There are 25 ribbons in a box. 9 ribbons are added to the box and k ribbons are taken away. How many ribbons are left in the box now?
k + 25
k + 9
k − 25
• 34 − k
Answer: 34 − k
Ribbons in a box = 25
Ribbons added = 9
Ribbons taken away = k
Ribbons left = 25 + 9 − k =34 k
'k taken away from 34' is equivalent to '34 − k' in symbols.


21. Bill had 20 blue ribbons and y green ribbons. He lost 3 blue ribbons and 3 green ribbons. What is the total number of ribbons Bill has now?
y + 20
y − 14
y + 14
• 14 − y
Answer: y + 14
Ribbons Bill had = y +20 
Ribbons Bill lost = 3 + 3 = 14
Total ribbons  Bill now has =y + 20 − 14 = y + 14
'lost 14 from y + 20' is equivalent to 'y + 20 − 14' in symbols.



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