**Solution:**
The hare and the tortoise are together covering the distance at 10 miles per hour (i.e., on adding their speeds).

So, they will cover the distance of 30 miles in 3 hours.

Thus, in 3 hours, they will meet and the hare will have traveled 27 miles.

**Alternative Solution through Equations:**
Note that : Distance = Speed × Time

Let

*t* be the time before the hare and the tortoise meet.

In

*t* hours, the hare will travel 9

*t* miles.

In

*t* hours, the tortoise will travel 1

*t* miles.

Now,

9

*t* + 1

*t* = 30

So,

*t* = 30 ⁄ 10 = 3 hours.

Thus, distance traveled by hare before meeting = 9 × 3 = 27 miles.

**Food for thought:**
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