Solution:
The hare and the tortoise are together covering the distance at 10 miles per hour (i.e., on adding their speeds).
So, they will cover the distance of 60 miles in 6 hours.
Thus, in 6 hours, they will meet and the hare will have traveled 48 miles.
Alternative Solution through Equations:
Note that : Distance = Speed × Time
Let
t be the time before the hare and the tortoise meet.
In
t hours, the hare will travel 8
t miles.
In
t hours, the tortoise will travel 2
t miles.
Now,
8
t + 2
t = 60
So,
t = 60 ⁄ 10 = 6 hours.
Thus, distance traveled by hare before meeting = 8 × 6 = 48 miles.
Food for thought:
Wish to try a more challenging puzzle similar in concept to this one?
Then click here.