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| Find the value of the algebraic expression by substituting the given value of the variable. |
1. k + 24.0 where k = 11.7
Answer: 35.7240 + 117 = 357
There is 1 decimal place in the numbers being added.
So the sum must have 1 decimal place.
Thus, 24.0 + 11.7 = 35.7
2. t + 33.7 where t = 25.2
Answer: 58.9337 + 252 = 589
There is 1 decimal place in the numbers being added.
So the sum must have 1 decimal place.
Thus, 33.7 + 25.2 = 58.9
3. 5.76 + f where f = 1.47
Answer: 7.23576 + 147 = 723
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 5.76 + 1.47 = 7.23
4. 23.80 + g where g = 10.89
Answer: 34.692380 + 1089 = 3469
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 23.80 + 10.89 = 34.69
5. 39.59 + d where d = 18.19
Answer: 57.783959 + 1819 = 5778
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 39.59 + 18.19 = 57.78
6. g − 5.6 where g = 12.3
Answer: 6.7123 − 56 = 67
There is 1 decimal place in the numbers being subtracted.
So the difference must have 1 decimal place.
Thus, 12.3 − 5.6 = 6.7
7. k − 4.9 where k = 14.5
Answer: 9.6145 − 49 = 96
There is 1 decimal place in the numbers being subtracted.
So the difference must have 1 decimal place.
Thus, 14.5 − 4.9 = 9.6
8. 13.87 − a where a = 7.34
Answer: 6.531387 − 734 = 653
There are 2 decimal places in the numbers being subtracted.
So the difference must have 2 decimal places.
Thus, 13.87 − 7.34 = 6.53
9. 16.47 − h where h = 10.77
Answer: 5.701647 − 1077 = 570
There are 2 decimal places in the numbers being subtracted.
So the difference must have 2 decimal places.
Thus, 16.47 − 10.77 = 5.70
10. r × 0.4 where r = 1.6
Answer: 0.644 × 16 = 64
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 0.4 × 1.6 = 0.64
11. 0.7 × j where j = 6
Answer: 4.27 × 6 = 42
There is 1 decimal place in the multiplicand and 0 in the multiplier.
So the product must have 1 + 0 = 1 decimal place.
Thus, 0.7 × 6 = 4.2
12. g × 3.8 where g = 5.1
Answer: 19.3851 × 38 = 1938
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 5.1 × 3.8 = 19.38
13. m × 4.3 where m = 7.2
Answer: 30.9672 × 43 = 3096
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 7.2 × 4.3 = 30.96
14. 0.32 × e where e = 7
Answer: 2.2432 × 7 = 224
There are 2 decimal places in the multiplicand and 0 in the multiplier.
So the product must have 2 + 0 = 2 decimal places.
Thus, 0.32 × 7 = 2.24
15. q ÷ 0.7 where q = 1.54
Answer: 2.215.4 ÷ 7 [Multiplied divisor and dividend by 10]
Now, 154 ÷ 7
= 22 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 1.54 ÷ 0.7 = 2.2
16. q ÷ 0.2 where q = 0.64
Answer: 3.26.4 ÷ 2 [Multiplied divisor and dividend by 10]
Now, 64 ÷ 2
= 32 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 0.64 ÷ 0.2 = 3.2
17. q ÷ 0.4 where q = 4
Answer: 1248 ÷ 4 [Multiplied divisor and dividend by 10]
Now, 48 ÷ 4
= 12 There is 0 decimal place in thedividend so the quotient must have 0 decimal place.
Thus, 4 ÷ 0.4 = 12
18. w ÷ 0.2 where w = 7
Answer: 3672 ÷ 2 [Multiplied divisor and dividend by 10]
Now, 72 ÷ 2
= 36 There is 0 decimal place in thedividend so the quotient must have 0 decimal place.
Thus, 7 ÷ 0.2 = 36
19. g ÷ 3.7 where g = 32.19
Answer: 8.7321.9 ÷ 37 [Multiplied divisor and dividend by 10]
Now, 3219 ÷ 37
= 87 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 32.19 ÷ 3.7 = 8.7
20. y ÷ 1.2 where y = 15.24
Answer: 12.7152.4 ÷ 12 [Multiplied divisor and dividend by 10]
Now, 1524 ÷ 12
= 127 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 15.24 ÷ 1.2 = 12.7
Try the Quiz : Algebraic Expressions - Evaluation 3
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