|
Hide all answers
Hide all answers
View all answers
View all answers
Print
Try the Quiz
| Find the value of the algebraic expression by substituting the given value of the variable. |
1. k + 36.0 where k = 19.6
Answer: 55.6360 + 196 = 556
There is 1 decimal place in the numbers being added.
So the sum must have 1 decimal place.
Thus, 36.0 + 19.6 = 55.6
2. t + 34.5 where t = 24.8
Answer: 59.3345 + 248 = 593
There is 1 decimal place in the numbers being added.
So the sum must have 1 decimal place.
Thus, 34.5 + 24.8 = 59.3
3. 7.63 + f where f = 2.32
Answer: 9.95763 + 232 = 995
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 7.63 + 2.32 = 9.95
4. 19.14 + g where g = 14.53
Answer: 33.671914 + 1453 = 3367
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 19.14 + 14.53 = 33.67
5. 35.59 + d where d = 13.74
Answer: 49.333559 + 1374 = 4933
There are 2 decimal places in the numbers being added.
So the sum must have 2 decimal places.
Thus, 35.59 + 13.74 = 49.33
6. g − 4.0 where g = 13.7
Answer: 9.7137 − 40 = 97
There is 1 decimal place in the numbers being subtracted.
So the difference must have 1 decimal place.
Thus, 13.7 − 4.0 = 9.7
7. k − 3.4 where k = 13.2
Answer: 9.8132 − 34 = 98
There is 1 decimal place in the numbers being subtracted.
So the difference must have 1 decimal place.
Thus, 13.2 − 3.4 = 9.8
8. 13.35 − a where a = 9.48
Answer: 3.871335 − 948 = 387
There are 2 decimal places in the numbers being subtracted.
So the difference must have 2 decimal places.
Thus, 13.35 − 9.48 = 3.87
9. 19.42 − h where h = 10.43
Answer: 8.991942 − 1043 = 899
There are 2 decimal places in the numbers being subtracted.
So the difference must have 2 decimal places.
Thus, 19.42 − 10.43 = 8.99
10. r × 0.4 where r = 1.2
Answer: 0.484 × 12 = 48
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 0.4 × 1.2 = 0.48
11. 0.3 × j where j = 6
Answer: 1.83 × 6 = 18
There is 1 decimal place in the multiplicand and 0 in the multiplier.
So the product must have 1 + 0 = 1 decimal place.
Thus, 0.3 × 6 = 1.8
12. g × 3.5 where g = 5.2
Answer: 18.2052 × 35 = 1820
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 5.2 × 3.5 = 18.20
13. m × 5.0 where m = 8.3
Answer: 41.5083 × 50 = 4150
There is 1 decimal place in the multiplicand and 1 in the multiplier.
So the product must have 1 + 1 = 2 decimal places.
Thus, 8.3 × 5.0 = 41.50
14. 0.25 × e where e = 4
Answer: 1.0025 × 4 = 100
There are 2 decimal places in the multiplicand and 0 in the multiplier.
So the product must have 2 + 0 = 2 decimal places.
Thus, 0.25 × 4 = 1.00
15. q ÷ 0.6 where q = 1.38
Answer: 2.313.8 ÷ 6 [Multiplied divisor and dividend by 10]
Now, 138 ÷ 6
= 23 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 1.38 ÷ 0.6 = 2.3
16. q ÷ 0.5 where q = 1.05
Answer: 2.110.5 ÷ 5 [Multiplied divisor and dividend by 10]
Now, 105 ÷ 5
= 21 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 1.05 ÷ 0.5 = 2.1
17. q ÷ 0.4 where q = 6
Answer: 1664 ÷ 4 [Multiplied divisor and dividend by 10]
Now, 64 ÷ 4
= 16 There is 0 decimal place in thedividend so the quotient must have 0 decimal place.
Thus, 6 ÷ 0.4 = 16
18. w ÷ 0.6 where w = 21
Answer: 36216 ÷ 6 [Multiplied divisor and dividend by 10]
Now, 216 ÷ 6
= 36 There is 0 decimal place in thedividend so the quotient must have 0 decimal place.
Thus, 21 ÷ 0.6 = 36
19. g ÷ 3.3 where g = 33.33
Answer: 10.1333.3 ÷ 33 [Multiplied divisor and dividend by 10]
Now, 3333 ÷ 33
= 101 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 33.33 ÷ 3.3 = 10.1
20. y ÷ 1.5 where y = 18.15
Answer: 12.1181.5 ÷ 15 [Multiplied divisor and dividend by 10]
Now, 1815 ÷ 15
= 121 There is 1 decimal place in thedividend so the quotient must have 1 decimal place.
Thus, 18.15 ÷ 1.5 = 12.1
Try the Quiz : Algebraic Expressions - Evaluation 3
|
