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From: ratchet | Reply 121 of 193 | Reply | |
Subject: Contributed Answer/Explanation to Q. 1 |
Rs. 4250
Given, Time(t)=2yrs
Rate%(r)=4%
Interest(I)=Rs.340
Let,Principal be "P"
I=P*t*r/100
340=P*2*4/100
P=340*100/2*4
P=4250
Therefore, The sum of money on which Interest is calculated is Rs.4250.
Posted at: Sun Mar 28 03:26:01 2010 (GMT)
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From: appas94 | Reply 122 of 193 | Reply | |
Subject: Contributed Answer/Explanation to Q. 2 |
85
CI = P[(1+R/200)2n-1]
CI =4250(1+4/200)1/2*2
CI = 4250*[51/50-1]
CI = 4250*1/50
CI = 85
Posted at: Sun Mar 28 11:02:08 2010 (GMT)
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From: shashwat95 | Reply 123 of 193 | Reply | |
Subject: wrong |
you missed a decimal
its 42.483 i got when i divided by 6 months!! Posted at: Mon Mar 29 01:55:27 2010 (GMT)
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From: kaustubh_mokashi | Reply 124 of 193 | Reply | View replies (1)
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Subject: Contributed Answer/Explanation to Q. 1 |
ans
I = 340
P= ?
R=4
T=2
S.I = PRT / 100
340 = P x 4 x 2 / 100
340 = 8P/100
340 x 100/8 = P
P= 4250
Posted at: Mon Mar 29 02:40:54 2010 (GMT)
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From: kaustubh_mokashi | Reply 125 of 193 | Reply | |
Subject: Contributed Answer/Explanation to Q. 1 |
ans
I = 340
P= ?
R=4
T=2
S.I = PRT / 100
340 = P x 4 x 2 / 100
340 = 8P/100
340 x 100/8 = P
P= 4250
Posted at: Mon Mar 29 02:41:25 2010 (GMT)
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From: kaustubh_mokashi | Reply 126 of 193 | Reply | |
Subject: Contributed Answer/Explanation to Q. 2 |
ans
P= 4250 Rs.
R= 4 % = 2%
T=2 years = 4 years
A=P(1 + R/100)n
A=4250(1 + 2/100)4
A= 4250(51/50)4
A= 4250 x 51/50 x 51/50 x 51/50 x 51/50
A= 4250 x 6765201/6250000
A= 4600.33
Posted at: Mon Mar 29 02:51:09 2010 (GMT)
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From: poojagiri04 | Reply 127 of 193 | Reply | |
Subject: Contributed Answer/Explanation to Q. 2 |
CI= Rs 171.7
SI = 340
T= 2 YRS
R = 4%
P= SI * 100/ RT
= 34000/2*4
=RS 4250
A= P (1+ R/200)^2n
= 4250*51*51/2500
A= RS 4421.7
CI= RS 171.7
Posted at: Fri Apr 2 08:55:41 2010 (GMT)
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From: poojagiri04 | Reply 128 of 193 | Reply | |
Subject: Contributed Answer/Explanation to Q. 4 |
ANS = 5
Posted at: Fri Apr 2 09:00:54 2010 (GMT)
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From: mona21 | Reply 129 of 193 | Reply | |
Subject: wrong ans |
how can u say ANG DAC and ANG ACB are alternate opposite angles. How come u
can think that AD is parallel to BC its neither anywhere mentioned or
depicted... Posted at: Sat Apr 3 13:10:59 2010 (GMT)
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From: misrasimi | Reply 130 of 193 | Reply | |
Subject: Contributed Answer/Explanation to Q. 24 |
LHS=RHS
LHS
=sinA/(1+cosA)
=sinA(1-cosA)/(1+cosA)(1-cosA)
=sinA(1-cosA)/(1-cos2A)
=sinA(1-cosA)/sin2A
=(1-cosA)/sinA
=1/sinA-cosA/sinA
=cosecA-cotA
= RHS
Posted at: Mon Apr 12 01:26:25 2010 (GMT)
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From: sidhartharyan | Reply 131 of 193 | Reply | View replies (2)
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Subject: Contributed Answer/Explanation to Q. 1 |
Rs.4250
Given,
P=?
R=4% per annum
T=2 years
As per the Formula,
S.I=P*R*T/100
340=(P*2*4)/100
340=(P*8)/100
P=340/8/100
P=340*100/8
P=34000/8
P=4250 (Ans)
I'm a student of STEWART SCHOOL, BHUBANESWAR, ODISHA.I am taught by Mr.
Dilip Kumar Behera at School and Mr. Sarat Sarangi at Tution. Both are our
School Teachers.
Posted at: Wed Apr 28 17:50:44 2010 (GMT)
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From: sidhartharyan | Reply 132 of 193 | Reply | View replies (2)
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Subject: Contributed Answer/Explanation to Q. 20 |
Rs 254.9
Principal for January = Rs. 2002
" " Feb = Rs. 2002
" " March = Rs. 2852
" " April = Rs.1722
" " May = Rs. 2372
" " June = Rs. 1795
Total Principal from Jan to June = Rs. 12745
Interest = (P*R*T)/100;
= (12745*4*6/12)100
= Rs. 254.9
Posted at: Wed Apr 28 18:16:34 2010 (GMT)
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From: sidhartharyan | Reply 133 of 193 | Reply | |
Subject: Contributed Answer/Explanation to Q. 20 |
Rs 254.9
Principal for January = Rs. 2002
" " Feb = Rs. 2002
" " March = Rs. 2852
" " April = Rs.1722
" " May = Rs. 2372
" " June = Rs. 1795
Total Principal from Jan to June = Rs. 12745
Interest = (P*R*T)/100;
= (12745*4*6/12)/100
= Rs. 254.9
Posted at: Wed Apr 28 18:18:23 2010 (GMT)
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From: sidhartharyan | Reply 134 of 193 | Reply | |
Subject: Contributed Answer/Explanation to Q. 1 |
Rs.4250
Given,
P=?
R=4% per annum
T=2 years
As per the Formula,
S.I=P*R*T/100
340=(P*2*4)/100
340=(P*8)/100
P=340/8/100
P=340*100/8
P=34000/8
P=4250 (Ans)
I'm a student of STEWART SCHOOL, BHUBANESWAR, ODISHA. I am being taught by
Mr. Dilip Kumar Behera at School and Mr. Sarat Sarangi at Tution. Both are
our School Teachers.
Posted at: Wed Apr 28 18:20:41 2010 (GMT)
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From: sidhartharyan | Reply 135 of 193 | Reply | |
Subject: Contributed Answer/Explanation to Q. 1 |
Rs.4250
Given,
P=?
R=4% per annum
T=2 years
As per the Formula,
S.I=P*R*T/100
340=(P*2*4)/100
340=(P*8)/100
P=340/8/100
P=340*100/8
P=34000/8
P=4250 (Ans)
I'm a student of STEWART SCHOOL, BHUBANESWAR, ODISHA. I am being taught by
Mr. Dilip Kumar Behera at School and Mr. Sarat Sarangi at Tution. Both are
our School Teachers.
Posted at: Wed Apr 28 18:20:48 2010 (GMT)
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From: sravansajeev96 | Reply 136 of 193 | Reply | |
Subject: Contributed Answer/Explanation to Q. 1 |
4250
I=PRT/100
340=P*4*2/100
340*100=8P
P=340*100/8
P=34000/8
P=4250.
Posted at: Thu May 27 02:50:39 2010 (GMT)
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From: pranav14595 | Reply 137 of 193 | Reply | |
Subject: Pranav |
after getting 16a/-10c=16b/-10d
ull have to apply alternendo
to get a/b=c/d Posted at: Sat May 29 13:43:47 2010 (GMT)
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From: replyshubham | Reply 138 of 193 | Reply | |
Subject: Simple Interest |
since SI= (PRT)/100
therefore
340x100= P x 4 x 2
P=(340x100)/8
P=34000/8
P=Rs.4250 Posted at: Sun May 30 07:16:32 2010 (GMT)
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From: pushp9343 | Reply 139 of 193 | Reply | |
Subject: Contributed Answer/Explanation to Q. 1 |
4250
4250
Posted at: Sun May 30 16:48:35 2010 (GMT)
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From: sanjana14 | Reply 140 of 193 | Reply | |
Subject: Contributed Answer/Explanation to Q. 1 |
Rs 4250
SI=340 Rs T=2YRS RATE=4%
Therefore P=SI*100/T*R
P=340*100/2*4
P=Rs. 4250
Posted at: Sat Jun 26 04:25:33 2010 (GMT)
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