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| From: priyal | Reply 41 of 193 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 10 |
r=7%
m.i = 300
t= 2 yrs
n= 2 *12 = 24
e.p = 300*24*25/2=rs 12*25*300
interest = 12*25*300*r*1/100*12
=75r
m.v=(m.i*24)+ interest
7725=(300*24)+75r
75r=525
r=7%
Posted at: Sun Jan 10 05:33:12 2010 (GMT)
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| From: priyal | Reply 42 of 193 | Reply | View replies (1)
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| Subject: Contributed Answer/Explanation to Q. 24 |
a proof doesnt hve an answer..
sin a/1 + cos a =
sin a (1- cos a)/(1+ cos a) (1-cos a)
= sin a (1- cos a)/1-cos2a
but 1- cos2a = sin2a
therefore
= sin a (1- cos a)/sin2a
=1 - cos a/sin a
= (1/sin a )-(cos a/sin a)
=cosec a - cot a
hence proved !
Posted at: Sun Jan 10 06:02:26 2010 (GMT)
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| From: priyal | Reply 43 of 193 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 24 |
a proof doesnt hve an answer..
sin a/1 + cos a =
sin a (1- cos a)/(1+ cos a) (1-cos a)
= sin a (1- cos a)/1-cos2a
but 1- cos2a = sin2a
therefore
= sin a (1- cos a)/sin2a
=1 - cos a/sin a
= (1/sin a )-(cos a/sin a)
=cosec a - cot a
hence proved !
Posted at: Sun Jan 10 06:05:02 2010 (GMT)
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| From: sanjana82 | Reply 44 of 193 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 27 |
0.34,-2.34
Posted at: Sun Jan 10 17:11:15 2010 (GMT)
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| From: tahir_sultantannery | Reply 45 of 193 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 1 |
4250
Posted at: Tue Jan 12 15:25:53 2010 (GMT)
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| From: tahir_sultantannery | Reply 46 of 193 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 2 |
346.36
Posted at: Tue Jan 12 15:35:24 2010 (GMT)
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| From: tahir_sultantannery | Reply 47 of 193 | Reply | View replies (3)
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| Subject: Contributed Answer/Explanation to Q. 3 |
hence proved
Posted at: Tue Jan 12 15:36:57 2010 (GMT)
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| From: aishugk | Reply 48 of 193 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 16 |
1
sin 25.cos65+cos 25.sin 65
sin(90-65).cos 65+cos(90-65).sin 65
cos 65.cos 65+sin 65.sin 65
cos^2 65 + sin ^2 65=1
Posted at: Sat Jan 16 11:58:33 2010 (GMT)
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| From: aishugk | Reply 49 of 193 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 20 |
39.65
jan 2002
feb 2002
march 2002
april 1722
may 2372
june 1795
total principal = 11895
interest =(11895*4)/(100*12)
=Rs 39.65~=Rs 40
Posted at: Sat Jan 16 12:16:59 2010 (GMT)
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| From: aishugk | Reply 50 of 193 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 42 |
2:5
Posted at: Sat Jan 16 13:15:49 2010 (GMT)
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| From: aishugk | Reply 51 of 193 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 43 |
2:3
Posted at: Sat Jan 16 13:16:37 2010 (GMT)
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| From: silverstead_sooraj | Reply 52 of 193 | Reply | View replies (1)
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| Subject: Contributed Answer/Explanation to Q. 4 |
5
f(2) = 0
2(2x2x2)-(2x2)-2p-2 = 0
16-4-2p-2 = 0
12-2p-2 = 0
10-2p =0
-2p = -10
2p = 10
p = 10/2
= 5
Posted at: Sun Jan 17 13:50:46 2010 (GMT)
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| From: silverstead_sooraj | Reply 53 of 193 | Reply | View replies (1)
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| Subject: Contributed Answer/Explanation to Q. 8 |
Rs.1696
Listed Price = Rs.1600
Sales tax to be paid by the coustumer = 1600x6/100
= Rs.96
Total Amount to be paid by the costumer = Listed price + Sales Tax
= 1600+96
= Rs.1696
Posted at: Sun Jan 17 14:01:07 2010 (GMT)
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| From: silverstead_sooraj | Reply 54 of 193 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 9 |
Rs.19.20
Tax Paid by the shopkeeper = Rs. 76.80
Tax Charged by the shopkeeper = Rs.96
VAT= Tax Charged-Tax Paid
= 96-76.80
=Rs.19.20
Posted at: Sun Jan 17 14:06:18 2010 (GMT)
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| From: silverstead_sooraj | Reply 55 of 193 | Reply | View replies (1)
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| Subject: Contributed Answer/Explanation to Q. 11 |
[4 1 1 -6]
Everyone must know this answer its so easy.
Posted at: Sun Jan 17 14:10:49 2010 (GMT)
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| From: ali_saj | Reply 56 of 193 | Reply | |
| Subject: Thanking you |
you are a good solver.. Posted at: Sun Jan 24 06:49:30 2010 (GMT)
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| From: rajagopal_1024 | Reply 57 of 193 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 5 |
(x-2)(2x+1)(x+1)
Posted at: Mon Jan 25 14:31:39 2010 (GMT)
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| From: rajagopal_1024 | Reply 58 of 193 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 29 |
56 degree
Posted at: Mon Jan 25 14:45:33 2010 (GMT)
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| From: rajagopal_1024 | Reply 59 of 193 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 34 |
39.9 m
Posted at: Mon Jan 25 14:53:34 2010 (GMT)
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| From: rajagopal_1024 | Reply 60 of 193 | Reply | |
| Subject: Contributed Answer/Explanation to Q. 42 |
4:9
Posted at: Mon Jan 25 14:57:58 2010 (GMT)
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